Ask question

Ask question

All categories

4 years ago

10

Solve the following system of equations. Express your answer as an ordered pair in the format (a,b) with no spaces between the n

umber or symbols. 2x+5y=16 -5x-2y=2

1 answer:

Westkost [7]4 years ago

6 0

The answer is 0 because 2+5 is 7 and then 5-2 is 7

You might be interested in

. A tennis supply store pays a wholesaler $90 for a tennis racquet and sells it for $144. What is the markup rate?

I am Lyosha [343]

Formula : Amount of change / Original amount

1. 144 - 90/ 144

2. Subtract 144 and 90

3. 54/ 144

4. Divide 54 by 144

5 0.375

6 Move the decimal two places to the right.

7. 37.5 %

Answer: 37.5% is the markup rate

6 0

3 years ago

Please help!!!!due at 11 .I think the number of sodas sold was 48 but I don't know how many hotdogs were sold

Alex Ar [27]

Answer:

Number of sodas sold: 78

Number of hot dogs sold: 24

Step-by-step explanation:

Number of sodas sold = x

Number of hot dogs sold = x - 54

Total number of sodas and hot dogs = x + x - 54 = 2x - 54

Total number = 102

2x - 54 = 102

2x = 156

x = 78

Number of sodas sold = x = 78

Number of hot dogs sold = x - 54 = 78 - 54 = 24

Answer:

Number of sodas sold: 78

Number of hot dogs sold: 24

6 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

Read 2 more answers

15=29-x<br> x=??????????????

zhuklara [117]

15 = 29 - x

15 + x = 29

x = 29 - 15

x = 14

6 0

3 years ago

Please help. Picture uploaded below.

sukhopar [10]

Answer: The answer is the number of each type of topping ordered.

7 0

2 years ago