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2 years ago

Find an equivalent ratio in simplest terms: 12 : 40

Mathematics

1 answer:

ANTONII [103]2 years ago

3 0

Answer:

3:10

Step-by-step explanation:

The GCF of 12 and 40 is 4.

$12:40 = 12/4:40/4 = \boxed{3 : 10}$

Hope this helps.

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Answer:

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the fourth is y=-x+2

Step-by-step explanation:

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FOR AN EXAM DUE TODAY!!! Simplify the polynomial. 3x – 2x2 + 4 – x2 + x + -

Mashutka [201]

Answer:

${ \tt{ \blue{ - {3x}^{2} + 4x + 4 }}}$

Step-by-step explanation:

${ \tt{3x - {2x}^{2} + 4 - {x}^{2} + x }} \\$

» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants

$= { \tt{( - 2 - 1) {x}^{2} + (3 + 1)x + 4 }} \\ = { \boxed{ \tt{ \: - {3x}^{2} + 4x + 4}}}$

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3 years ago

Solve the following system by any method -8x-8y=0 -8x+2y=-20

iVinArrow [24]

$\fbox{Solution by using Matrix}$

$\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20$

$\text{Rewrite the linear equations above as a matrix}$

$\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right]$

$\text{Apply to Row2 : Row2 + Row1}$

$\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right]$

$\text{Note: The matrix is now in echelon form.}$ $\text{The steps below are for back substitution.}$

$\text{Apply to Row1 : Row1 + 8 Row2}$

$\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right]$

$\text{ Simplify rows}$

$\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right]$

$\text{Therefore, the solution is}$

$x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}$

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3 years ago

Find an equivalent ratio in simplest terms: 12 : 40​

Find an equivalent ratio in simplest terms: 12 : 40