All categories

3 years ago

I need help on the question!!!

Mathematics

1 answer:

vladimir2022 [97]3 years ago

7 0

Answer:

4 and 6

Step-by-step explanation:

Look at the ways 24 can be written as a product.

24 = 1×24 = 2×12 = 3×8 = 4×6

The sums of these factors are 25, 14, 11, 10. The factor pair you're looking for is the one that has a sum of 10:

4 and 6

You might be interested in

A blender runs at 120 volts at 4.16 amps. Calculate power

andrey2020 [161]

Answer:

P = 499.2 Watt

Step-by-step explanation:

$p = iv \\ p = 4.16 \times 120 \\ p = 499.2 \: watt$

6 0

3 years ago

Asap! find the length of the arc

Fantom [35]

Answer:

A. $\frac{21}{4} \pi\ \space\ in$

Step-by-step explanation:

The formula for arc length is:

arc length = rθ

where:

r is the radius = 7 in

θ is the central angle in radians = 135 × $\frac{ \space\ \pi\ }{180}$ = 3/4 π

Substituting these values into the formula:
arc length = 7 in × 3/4 π

= $\frac{21}{4} \pi\ \space\ in$

6 0

2 years ago

The sum of the angle measures of a polygon with s sides is 2880. Find s. A. 20 B. 16 C. 17 D. 18

siniylev [52]

I think the answer is D. 18

8 0

3 years ago

Rewrite in Polar Form.... x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago

Help me please ..........................

attashe74 [19]

Step-by-step explanation:

3 0

3 years ago