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2 years ago

When Mrs. Carter got a flat tire, 73% of the 32 pounds of air in the tire escaped.

Mathematics

1 answer:

Lorico [155]2 years ago

8 0

Step-by-step explanation:

100% = 32

73% = 73×1% = 73×100%/100 = 73×32/100 = 23.36 pounds.

for an estimate I would round up to 75% = 3/4, and then calculate quickly 32 × 3/4 = 8×3 = 24 pounds.

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Sarawong had some candy to give to his four children. He first took nine pieces for himself and then evenly divided the rest amo

svet-max [94.6K]

9+3+3+3=21 or you could do 4*3+9

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2 years ago

Read 2 more answers

How does the job satisfaction score for weeks 5-8 compare to weeks 1-4?

MrRa [10]

The correct comparison for Weeks 5-8 is higher than Week 1-4, hence, the job satisfaction for Week 5-8 is 17% higher.

Job Satisfaction Score :

Week 1 = 3.50
Week 2 = 3.40
Week 3 = 3.30
Week 4 = 3.60
Week 5 = 4.20
Week 6 = 4.00
Week 7 = 4.10
Week 8 = 3.90

Job Satisfaction for week 1 - 4 :

Week 1 + Week 2 + Week 3 + Week 4
(3.50 + 3.40 + 3.30 + 3.60) = 13.80

Job Satisfaction for Week 5 - 8 :

Week 5 + Week 6 + Week 7 + Week 8
(4.20 + 4.00 + 4.10 + 3.90) = 16.20

Difference between the two categories :

[(Week 5 - 8) - (Week 1-4)] / Week 1-4] × 100%

(16.20 - 13.80) / 13.80 × 100%

(2.4 / 13.80) × 100%

0.1739 × 100%

= 17.39%

Therefore, the job satisfaction for Week 5 - 8 is about 17% higher than Week 1 - 4

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2 years ago

1,000,000,000 in scintiufci notioation

kolbaska11 [484]

1 x 10 to the 9th power

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2 years ago

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How do I solve this?

Tanya [424]

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3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago