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Makovka662 [10]
2 years ago
14

if there was a group of ten people the probability of two of them being born on the same day of the same week is 1? is this corr

ect yes or no explain you answer.
Mathematics
1 answer:
gladu [14]2 years ago
6 0

Answer:yes

Step-by-step explanation:

Im not that good but if there is a birth rate of 1000 people per day then if you estimate that awnser you have a possibility of 60%

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Write the simplified form of (-0.5z + 0.9z) – (-0.3z + 0.9z).
Delicious77 [7]

Answer:

-0.2z

Step-by-step explanation:

0.4z-0.6z

-0.2z

8 0
2 years ago
How to estimate and multiply 83x367
Neporo4naja [7]
Use a calculator yo help you get it
3 0
3 years ago
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A total of 165 people attended the opening night of a school play. Adults were charged $6, and children were charged $2. The tot
arlik [135]
-------------------------------------------------------------------------
Given Information
-------------------------------------------------------------------------
Total number of people = 165
Adult = $6
Child = $2
Total collected = $618

-------------------------------------------------------------------------
Assumptions 
-------------------------------------------------------------------------
Let x be the number of adults and y be the number of children

-------------------------------------------------------------------------
Form equations
-------------------------------------------------------------------------
Total number of people
x + y = 165
Total amount collected 
6x + 2y = 618

-------------------------------------------------------------------------
Ans: The two equations are x + y = 165 and 6x + 2y = 618
-------------------------------------------------------------------------


The question is not asking for it but if you need to solve the equation to find the answer to x and y

-------------------------------------------------------------------------
Present the two equations and solve for x and y
-------------------------------------------------------------------------
x + y = 165          ------------------------- (eqn 1)
6x + 2y = 618      ------------------------- (eqn 2)

(eqn 1) : 
x + y = 165
x = 165 - y -------------------------  substitute into (eqn 2)

6(165 - y) + 2y = 618
990 - 6y + 2y = 618
4y = 990 - 618
4y = 372
y = 93 -------------------------  substitute into (eqn 1)

x + y = 165
x + 93 = 165
x = 165 - 93
x = 72 

x = 72 and y = 93

-------------------------------------------------------------------------
Ans: 72 adults and 93 children
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5 0
3 years ago
Read 2 more answers
find the equation of the perpendicular bisector of the line segment joining the points (3,8) and (-5,6).​
IgorLugansk [536]

Answer:

y = - 4x + 3

Step-by-step explanation:

The perpendicular bisector is positioned at the midpoint of AB at right angles.

We require to find the midpoint and slope m of AB

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = A(3, 8) and (x₂, y₂ ) = B(- 5, 6)

m = \frac{6-8}{-5-3} = \frac{-2}{-8} = \frac{1}{4}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{4} } = - 4

mid point  = [0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

Using the coordinates of A and B, then

midpoint AB = [0.5(3 - 5), 0.5(8 + 6) ] = (- 1, 7 )

Equation of perpendicular in slope- intercept form

y = mx + c ( m is the slope and c the y- intercept )

with m = - 4

y = - 4x + c ← is the partial equation

To find c substitute (- 1, 7) into the partial equation

Using (- 1, 7), then

7 = 4 + c ⇒ c = 7 - 4 = 3

y = - 4x + 3 ← equation of perpendicular bisector

3 0
3 years ago
Read 2 more answers
A slot machine has 3 slots. For each slot, the possible outcomes are an apple, orange, lemon, banana, melon, and a joker. When t
PolarNik [594]

Answer:

1. 15

2. 75

Step-by-step explanation:

The possible outcomes are an apple (A), orange (O), lemon (L), banana (B), melon (M), and a joker (J), 6 outcomes in total.

1. You could win with 2 jokers in

5+5+5=15 different ways.

You can list all these ways:

JJA    JAJ   AJJ

JJO   JOJ   OJJ

JJL     JLJ    LJJ

JJB    JBJ    BJJ

JJM   JMJ    MJJ

2. You could win with 1 joker in

5\cdot 5+5\cdot 5+5\cdot 5=75different ways

You can list all these ways:

JAA    JAO   JAL   JAB   JAM

JOA    JOO   JOL   JOB   JOM

JLA     JLO    JLL    JLB    JLM

JBA    JBO    JBL    JBB   JBM

JMA    JMO   JML   JMB   JMM

AJA     AJO   AJL   AJB   AJM

OJA    OJO   OJL   OJB   OJM

LJA     LJO    LJL    LJB    LJM

BJA    BJO    BJL    BJB   BJM

MJA    MJO   MJL   MJB   MJM

AAJ    AOJ    ALJ    ABJ   AMJ

OAJ    OOJ   OLJ   OBJ   OMJ

LAJ     LOJ     LLJ    LBJ    LMJ

BAJ    BOJ     BLJ    BBJ   BMJ

MAJ    MOJ   MLJ   MBJ   MMJ

6 0
2 years ago
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