Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Answer:
w=5
Step-by-step explanation:
the triangle has the same size of area as the side of the rectangle so therefore 5
Answer:
by doing it the same way you did with the first one.
Step-by-step explanation:
Answer:
The center of the circle is:
Thus, option (2) is true.
Step-by-step explanation:
The circle equation is given by
here,
Given the equation
comparing with the circle equation
Therefore, the center of the circle is:
Thus, option (2) is true.
