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julia-pushkina [17]
3 years ago
6

SOMEBODY HELP ME AS SOON AS POSSIBLE !!

Mathematics
1 answer:
mixer [17]3 years ago
6 0

Answer:

387000000 (Question C)

Step-by-step explanation:

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Please anyone help me on this question
vazorg [7]

Answer:

a) 60

b) 0.24

c) 150

Step-by-step explanation:

a) P(green) = ⅕

Expected no. = 300 × ⅕

= 60

b) total = 300

P(purple) = 72/300

= 6/25 = 0.24

c) P(blue) = 45/300

= 3/20 = 0.15

Expected no.: 1000 × 0.15

= 150

5 0
2 years ago
a recipe serving 8 people calls for 5 pounds of apples and 2 cups of flour. you want to prepare the recipe for 24 people
Cloud [144]

15 pounds of apples and 6 cups of flour

6 0
3 years ago
Read 2 more answers
Choose Yes or No to tell if the number 3.23 will make each equation true.
Free_Kalibri [48]

Answer:

yes

no

yes

no

Step-by-step explanation:

i think its right

5 0
3 years ago
Read 2 more answers
Determine the solution to f(x) = g(x) using the following system of equations: f(x) = 3x + 12 g(x) = -9.5x - 13
Anit [1.1K]
Answer:

x=2

Step by step:
f(x)=g(x)

3x+12= -9.5x-13 simplifies to the equation below

3x+9.5x= -13-12

12.5x= -25
next, divide by 12 on both sides to isolate the variable, x.

12.5x/12 = -25/12

x=-2

to check: 3(-2)+12= -95x(-2)-13
-6+12= 19-13
6=6 ✅
7 0
2 years ago
Read 2 more answers
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
3 years ago
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