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dem82 [27]
3 years ago
13

Which of the following represents a financially responsible decision

Mathematics
1 answer:
jeyben [28]3 years ago
6 0
I just did this quiz and got a 100%  the answer is A) <span>Putting a small amount of money aside each month to use to purchase Christmas gifts. 


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William had $45 dollars to spend on Vegetables. After buying 6 watermelons , he had $25.50 left .how much did each watermelons c
notka56 [123]
Easy, just do 45-25.50= 19.50 and then divide 19.50 by 6, and then you get 3.25. So, your answer would be $3.25.
5 0
3 years ago
Write T times B times 3 as an expression
Triss [41]

Answer:

3 (t * b)

Step-by-step explanation:

Txbx3 expand-

3 (t * b)

*= times btw

4 0
3 years ago
A restaurant is offering 2 specials: 10 burritos for $12, or 6 burritos for $7.50. Noah needs 60 burritos for his party. Should
slega [8]

Answer:

6 orders of the 10 burrito special

Step-by-step explanation:

10 burritos for $12

60 burritos for $72.

6 burritos for $7.50

10 burritos for $75

So the 10 burritos for $12 is better.

Hope this helps :D

5 0
3 years ago
HELP ASAP 10 POINTS WILL MARK IF CORRECT
Nastasia [14]

Answer:

To get the slope, we can first mark out any 2 points of the line.

In this case, I will use the point (-2, 0) which will be (x1, y1) and (0, -2) which I will call (x2, y2).

To get the slope, you need to do \frac{y2-y1}{x2-x1}

Substitute these values in:

\frac{-2-0}{0-(-2)} =\frac{-2}{2} =-1

The slope is -1.

4 0
3 years ago
For all integers n, if n2 is odd, then n is odd. Use a proof by contraposition, as in Lemma 1.1. Let n be an integer. Suppose th
Reil [10]
Let's assume that the statement "if n^2 is odd, then is odd" is false. That would mean "n^2 is odd" leads to "n is even"

Suppose n is even. That means n = 2k where k is any integer.

Square both sides

n = 2k
n^2 = (2k)^2
n^2 = 4k^2
n^2 = 2*(2k^2)

The expression 2(2k^2) is in the form 2m where m is an integer (m = 2k^2) which shows us that n^2 is also even. 

So this contradicts the initial statement which forces n to be odd. 
8 0
3 years ago
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