Answer:
The answer is 386 feet.
Step-by-step explanation:
This equation simply asks to plug in a value that gives you the final value of the height. 450 is the initial height, and r (or l) is referred to as the amount of seconds after the item is dropped. 16 is the constant value of feet that the ball drops within one second.
Therefore, by substituting 4 for r (or l) and multiplying it by 16, you will receive 64 feet in 4 seconds. Finally, you need to subtract this from 450 feet, giving you a final answer of 386 feet.
When a number with an exponent is raised to an exponent, you multiply the two exponents together to get the combined exponent of the simplified version.
Let's take our exponents, 2 and 3, and multiply them.
2 x 3 = 6
Therefore we can apply the sixth power to 3a for our final answer of 3a⁶.
Hope this helped!
he volume of the solid under a surface
z
=
f
(
x
,
y
)
and above a region D is given by the formula
∫
∫
D
f
(
x
,
y
)
d
A
.
Here
f
(
x
,
y
)
=
6
x
y
. The inequalities that define the region D can be found by making a sketch of the triangle that lies in the
x
y
−
plane. The bounding equations of the triangle are found using the point-slope formula as
x
=
1
,
y
=
1
and
y
=
−
x
3
+
7
3
.
Here is a sketch of the triangle:
Intersecting Region
The inequalities that describe D are given by the sketch as:
1
≤
x
≤
4
and
1
≤
y
≤
−
x
3
+
7
3
.
Therefore, volume is
V
=
∫
4
1
∫
−
x
3
+
7
3
1
6
x
y
d
y
d
x
=
∫
4
1
6
x
[
y
2
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
y
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
49
9
−
14
x
9
+
x
2
9
−
1
]
d
x
=
3
∫
4
1
40
x
9
−
14
x
2
9
+
x
3
9
d
x
=
3
[
40
x
2
18
−
14
x
3
27
+
x
4
36
]
4
1
=
3
[
(
640
18
−
896
27
+
256
36
)
−
(
40
18
−
14
27
+
1
36
)
]
=
23.25
.
Volume is
23.25
.
Answer:
(2, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
2x + y = 5
3x - 2y = 4
<u>Step 2: Rewrite Systems</u>
<em>Manipulate 1st equation</em>
- [Subtraction Property of Equality] Subtract 2x on both sides: y = 5 - 2x
<u>Step 3: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [2nd Equation]: 3x - 2(5 - 2x) = 4
- [Distributive Property] Distribute -2: 3x - 10 + 4x = 4
- [Addition] Combine like terms: 7x - 10 = 4
- [Addition Property of Equality] Add 10 on both sides: 7x = 14
- [Division Property of Equality] Divide 7 on both sides: x = 2
<u>Step 4: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [Modified 1st Equation]: y = 5 - 2(2)
- Multiply: y = 5 - 4
- Subtract: y = 1
For this case we have the following expression:
p ^ 0
By properties of exponents we have:
Any number raised to the exponent zero is equal to one.
We have then, that applying this property:
p ^ 0 = 1
Answer:
the simplified form of p ^ 0 is:
D. 1
