2X+2+4=8
2X+6=8
-6 -6
_________
2X=2
_____
2 2
X=1
a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
$38.25 divided by 3 = $12.75
I think the answer is 12.75 because each shirt cost the same.
Answer:
your
Step-by-step explanation:
first we do
square is length 6 so base =6
10-6=4
the rectangle is 2 by 4
base=4
square is 6 by 6
rectangle is 4 by 2
split the triangles up
area of triangle=1/2base times height
rectangle triangle base=4
height=2, area=1/2 times 2 times 4=4
square triangle
flip 90 degrees clockwise so we have base=2
height=6
area=1/2 times 2 times 6=6
add
4+6=10
total area=10m^2
