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Mars2501 [29]
3 years ago
15

Pls answer fast my teacher is waiting!

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

For company A, y = 24x + 42

For company B, y = 28x + 25

Step-by-step explanation:

x is the number of containers

y is the total cost

For company A, y = 24x + 42

For company B, y = 28x + 25

For the cost of both companies to be the same, then

24x + 42 = 28x + 25

28x - 24x = 42 - 25

4x = 17

x = 4.25

Mr Lycan would have to order about 4 containers so the cost would be the same from each company

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In the right triangle shown, DF=EF=3DF=EF=3D, F, equals, E, F, equals, 3.
jarptica [38.1K]

Answer:

<h2>The side DE is 4.2 units long, approximately.</h2>

Step-by-step explanation:

In the given triangle, side DE is the hypothenuse. So, we can use Pythagorean's Theorem, where both legs are 3 units long.

DE^{2}=DF^{2}+EF^{2}\\ DE^{2}=3^{2}+3^{2}\\DE^{2}=9+9\\DE=\sqrt{18} \approx 4.2

Therefore, the side DE is 4.2 units long, approximately.

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3 years ago
A circular plate has a radius of 13 centimeters.
GarryVolchara [31]

Answer:

530.66 cm^2.

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

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