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Natali [406]
3 years ago
12

Which of the curves on the graph below indicate a function

Mathematics
1 answer:
Slav-nsk [51]3 years ago
6 0

Answer: Hello, I saw another picture and i think it was A

Step-by-step explanation: Vertical Line test will determine if a graph is a function or not

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Tate has 5 more than twice as many pennies as Mia. If Mia has x pennies, which equation can be used to find how many pennies she
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Answer:

3x + 5 = 30

Step-by-step explanation:

Tate has 2x + 5 pennies and since Tate and Mia have 30 pennies all together you would add an x to the equation of how many pennies Tate has and set it equal to 30 making the equation 3x + 5 = 30

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A student is asked to solve the equation below and to justify her/his steps. Identify what, if anything, is incorrect in her/his
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4 years ago
Irrational equations 64^1/3 how to simplify?
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For indicies, the numerator is the normal power, and the denominator is a root as such. So 1/2 would be square root, 1/3 would be cube root, 1/4 would be 4th root and so on.

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4 years ago
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SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school are given below
kvasek [131]

Answer:

The value of test statistics is 25.

Step-by-step explanation:

We are given below the SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school;

380, 520, 480, 510, 560, 630, 670, 490, 500, 550, 400, 350, 440, 490, 620, 660, 700, 730, 740, 560

<em>Let </em>\sigma<em> = population standard of the reading and writing section SAT score of the students in this school</em>

So, Null Hypothesis, H_0 : \sigma \leq 100     {means that the reading and writing section SAT score of the students in this school is lesser than or equal to 100}

Alternate Hypothesis, H_A : \sigma<em> </em>> 100     {means that the reading and writing section SAT score of the students in this school is higher than 100}

The test statistics that would be used here is <u>One-sample Chi-square</u> test statistics;

                        T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s^{2} = sample variance =  \frac{\sum (X-\bar X)^{2} }{n-1}  = 13135.8

            n = sample of 11th-grade students = 20

So, <u><em>the test statistics</em></u>  =  \frac{(20-1)\times 13135.8^{2} }{100^{2} }

                                     =  24.96 ≈ 25

Hence, the value of test statistics is 25.

5 0
4 years ago
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