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Ainat [17]
3 years ago
7

What is the volume of a cone with the height of 6 inches and the diameter of 4 inches?

Mathematics
1 answer:
Viktor [21]3 years ago
3 0
A is the answer because I had the answer on I ready
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What's 4/9 as a decimal
Shkiper50 [21]
ANSWER-
0.44 , Explanation- divide the numerator from the denominator
3 0
3 years ago
Read 2 more answers
Can u guys solve this for me pls ;)
vovangra [49]

ANSWER:

What I would to is look it up on google or brainly.

Step-by-step explanation:

8 0
3 years ago
F(x)=x^2 . what is g(x)?<br> please help ‍♀️
blagie [28]

Answer:

D) g(x) = 4x^2 because the given point works when it's plug in the equation.

Step-by-step explanation:

It's a vertical stretch so a>1 for the transformation

Definitely not C, since it's a shrink with 0<a<1.

Plug in the point to see which one works

g(x) = 16x^2

g(1) = 16. A is not right

B is the same thing to A

g(1) = (4*1)^2 = 16. So, B is also not right

For D:

g(1) = 4(1)^2 =4. Point (1,4) that's show on the graph works for this equation.

D is correct

7 0
3 years ago
S
Rudiy27

Answer:

<h2>(3, -2)</h2>

Step-by-step explanation:

Put the coordinates of the points to the inequality and check:

y < -1/2x + 2

for (2, 3) → x = 2, y = 3

3 < -1/2(2) + 2

3 < -1 + 2

3 < 1     FALSE

============================

for (2, 1) → x = 2, y = 1

1 < -1/2(2) + 2

1 < -1 + 2

1 < 1    FALSE

============================

for (3, -2) → x = 3, y = -2

-2 < -1/2(3) + 2

-2 < -1.5 + 2

-2 < 0.5      TRUE

============================

for (-1, 3) → x = -1, y = 3

3 < -1/2(-1) + 2

3 < 1/2 + 2

3 < 2 1/2      FALSE

6 0
4 years ago
At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 6 cubic feet per minute. The dia
Alla [95]

Answer:

0.2122\text{ ft per min}

Step-by-step explanation:

Let r be the radius ( in feet ) of the cone,

So, the diameter of the cone = 2 × radius = 2r feet,

∵ The diameter of the base of the cone is three times the height,

If h represents the height of the cone,

⇒ 2r = 3 × h,

⇒ r=\frac{3h}{2} feet,

∵ Volume of a cone,

V=\frac{1}{3}\pi R^2 H

Where,

R = radius, H = height,

Thus, the volume of the given cone is,

V=\frac{1}{3}\pi r^2 h

=\frac{1}{3}\pi (\frac{3h}{2})^2 h

=\frac{3}{4}\pi h^3

Differentiating with respect to t ( time )

\frac{dV}{dt}=\frac{9}{4}\pi h^2\frac{dh}{dt}

We have,

\frac{dV}{dt}=6\text{ cubic ft per min},h=2\text{ feet}

6=\frac{9}{4}\pi (2)^2 \frac{dh}{dt}

6=9\pi \frac{dh}{dt}

\implies \frac{dh}{dt}=\frac{6}{9\pi }\approx 0.2122\text{ ft per min}

4 0
4 years ago
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