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kogti [31]
2 years ago
6

Order these from least to greatest [25 points]

Mathematics
1 answer:
VMariaS [17]2 years ago
8 0

Answer:

\frac{\sqrt{6} }{4}, 1.538..., \frac{19}{7}, \sqrt{29}

Step-by-step explanation:

Solve them each on the calculator and then put in order

\frac{\sqrt{6} }{4} = 0.6123...

19/7 = 2.714

\sqrt{29} = 5.385...

You might be interested in
I will appreciate your help
KatRina [158]

Answer:

Hello! answer: 252

Step-by-step explanation:

To find parelogram area you do base × height so... 21 × 12 = 252 therefore 252 is the area Hope that helps!

4 0
3 years ago
Read 2 more answers
Work out the following, giving your answer in its simplest form
sveticcg [70]
I believe it would be 5/12
5 0
3 years ago
What is the distance between the set of points (5,9) and (-7,-7)
kiruha [24]

Answer:

The answer is

<h2>20 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(5,9) and (-7,-7)

The distance between them is

<h3>d =  \sqrt{ ({5 + 7})^{2} + ( {9 + 7})^{2}  }  \\  =  \sqrt{ {12}^{2} +  {16}^{2}  }  \\  =  \sqrt{144 + 256}  \\  =  \sqrt{400}</h3>

We have the final answer as

<h3>20 units</h3>

Hope this helps you

3 0
3 years ago
Solve the equation for the red variable .red variable is v. Equation is B=3•v/h
iogann1982 [59]

Hey there! :)

B = 3 · v/h

To solve for v, we must isolate the variable. To start off, let's first multiply both sides by h.

B · h = 3 · v/h · h

Simplify.

Bh = 3 · v

Simplify.

Bh = 3v

Divide both sides by 3.

Bh ÷ 3 = 3v ÷ 3

Simplify.

\frac{Bh}{3} = v

Therefore, our red variable is : v = \frac{Bh}{3}

~hope I helped!~

8 0
4 years ago
Find the cross product (7,9,6) x (-4,1,5). Is the resulting vector perpendicular to the given vectors
melisa1 [442]

Expand each vector as linear combinations of the standard basis vectors:

(7, 9, 6) = 7(1, 0, 0) + 9(0, 1, 0) + 6(0, 0, 1)

(-4, 1, 5) = -4(1, 0, 0) + (0, 1, 0) + 5(0, 0, 1)

For brevity, write

i = (1, 0, 0)

j = (0, 1, 0)

k = (0, 0, 1)

Then by definition of the cross product,

i x i = j x j = k x k = (0, 0, 0)

i x j = k

j x k = i

k x i = j

and for any two vectors a and b, we have a x b = - b x a.

Now compute the product:

(7i + 9j + 6k) x (-4i + j + 5k)

= -28 (i x i) - 36 (j x i) - 24 (k x i)

...   + 7 (i x j) + 9 (j x j) + 6 (k x j)

...   + 35 (i x k) + 45 (j x k) + 30 (k x k)

= -36 (-k) - 24 j + 7 k + 6 (-i) + 35 (-j) + 45 i

= 39 i - 59 j + 43 k

which is the same as the vector

(39, -59, 43)

And yes, this vector is perpendicular to both given vectors.

6 0
4 years ago
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