Uhmmm ma’am/sir i am not sure what’s going on exactly
I think that it is B, but i'm not sure
From the options given, the only option which would result on having a reduced error margin, is to increase the sample size.
<u>Recall</u><u> </u><u>:</u><u> </u>
<em>Margin of Error</em> = Zcritical × σ/√n
- Increasing the mean would have no impact on the margin of error as it is not a part of the factors which affects the margin of error value.
- Increasing the standard deviation, which is the Numerator will result in an increased margin of error value.
- By raising the confidence level, the critical value of Z will increase, hence widening the margin of error.
- The sample size, n being the denominator, would reduce the value of error margin.
Hence, only the sample size will cause a decrease in the margin of error of the interval.
Learn more : brainly.com/question/25569754
Answer:
look down
Explanation:
who ever is reading this is a joke