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Varvara68 [4.7K]
2 years ago
7

The expression 1.08s + 1.02b1.08s+1.02b1, point, 08, s, plus, 1, point, 02, b predicts the end-of-year value of a financial port

folio where sss is the value of stocks and bbb is the value of bonds in the portfolio at the beginning of the year. What is the predicted end-of-year value of a portfolio that begins the year with \$200$200dollar sign, 200 in stocks and \$100$100dollar sign, 100 in bonds?
SAT
1 answer:
Mice21 [21]2 years ago
5 0

the answer is 318 because that is the answer 318

                                             318

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Find the surface area of the square pyramid. a) 80 in2 b) 105 in2 c) 160 in2 d) 210 in2
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<h2>Right answer: I and II only </h2>

If we already have the formula to find how temperature measured in degrees Fahrenheit, relates to a temperature in degres Celsius:

C=(F-32)\frac{5}{9}    (1)

We can know the formula to find how temperature measured in degrees Celsius, relates to a temperature in degres Fahrenheit, only by isolating F:

F=(\frac{9}{5}C)+32    (2)

Having both formulas, let’s begin:

I) If we want to prove that a temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9 degree Celsius:

Beginning with 1\ºF:

C=(1\ºF-32)\frac{5}{9}=-17.22\ºC

This means: 1\ºF=-17.22\ºC

Now we are going to increase 1 degree Farenheit. In other words, we are going to use 2\ºF:

C=(2\ºF-32)\frac{5}{9}=-16.66\ºC

This means: 2\ºF=-16.66\ºC

Calculating the difference between -16.66\ºC   and  -17.22\ºC:

-16.66\ºC-(-17.22\ºC)=0,55\ºC>>>>This is equal to 5/9 degree Celsius, hence is correct

II) If we want to prove that a temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit:

Beginning with 1\ºC:

F=(\frac{9}{5}1\ºC)+32  

F=33.8\ºF  

This means: 1\ºC=33.8\ºF  

Now we are going to increase 1 degree Celsius. In other words, we are going to use 2\ºC:

F=(\frac{9}{5}2\ºC)+32  

F=35.67\ºF  

This means: 2\ºC=35.67\ºF  

Calculating the difference between 35.67\ºF   and  33.8\ºF:

35.67\ºF-33.8\ºF=1.8\ºF>>>>This is a proof of the statement, hence is also correct.

<h2 />

III) If we want to prove that a temperature increase of 5/9 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius:

Beginning with 1\ºC:

F=(\frac{9}{5}1\ºC)+32  

F=33.8\ºF  

This means: 1\ºC=33.8\ºF  

Now we are going to add \frac{5}{9}\ºF:

33.8\ºF+\frac{5}{9}\ºF=34.35\ºF

And use this value in the Celsius formula:

C=(34.35\ºF-32)\frac{5}{9}=1.30\ºC

This means: 1.30\ºC=34.35\ºF

In other words: An increase in 5/9 degree Fahrenheit is equivalent to a temperature increase of 1.30 degree Celsius, <u>not 1 degree Celsius</u>.

Therefore this statement is incorrect.

4 0
3 years ago
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