If a figure is a square then is it a regular quadrilateral true or false explain
1 answer:
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Answer:
Cost of adult ticket is $8 and Cost of children ticket is $5.
Step-by-step explanation:
Given:
Let the cost of each Adult ticket be 'x'.
Let the cost of each child ticket be 'y'.
Now Given:
The lee's spend $ 31 on movie tickets for 2 adults and 3 children.
Number of adult tickets = 2
Number of children ticket = 3
Total money spent = $31
So we can say that;
Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.
framing in equation form we get;
Also Given:
The Smith's spent $ 26 on movie tickets for 2 adults and 2 children
Number of adult tickets = 2
Number of children ticket = 2
Total money spent = $26
So we can say that;
Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.
framing in equation form we get;
Now Subtracting equation 2 from equation 1 we get;
Now substituting the value of y in equation 1 we get;
Hence Cost of adult ticket is $8 and Cost of children ticket is $5.
Isolate the root expression:
![\sqrt[3]{x+1}+2=0\implies\sqrt[3]{x+1}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%2B2%3D0%5Cimplies%5Csqrt%5B3%5D%7Bx%2B1%7D%3D-2)
Take the third power of both sides:
![\sqrt[3]{x+1}=-2\implies(\sqrt[3]{x+1})^3=(-2)^3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%3D-2%5Cimplies%28%5Csqrt%5B3%5D%7Bx%2B1%7D%29%5E3%3D%28-2%29%5E3)
Simplify:
![(\sqrt[3]{x+1})^3=(-2)^3\implies x+1=-8](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%2B1%7D%29%5E3%3D%28-2%29%5E3%5Cimplies%20x%2B1%3D-8)
Isolate and solve for
:
Since the cube root function is bijective, we know this won't be an extraneous solution, but it doesn't hurt to verify that this is correct. When, we have
![\sqrt[3]{-9+1}=\sqrt[3]{-8}=\sqrt[3]{(-2)^3}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-9%2B1%7D%3D%5Csqrt%5B3%5D%7B-8%7D%3D%5Csqrt%5B3%5D%7B%28-2%29%5E3%7D%3D-2)
as required.
Take the third power of both sides:
Simplify:
Isolate and solve for
Since the cube root function is bijective, we know this won't be an extraneous solution, but it doesn't hurt to verify that this is correct. When
as required.