Answer:
three <em>multipl</em><em>i</em><em>e</em><em>d</em><em> </em>by six <em>m</em><em>i</em><em>n</em><em>u</em><em>s</em><em> </em>one in <em>parentheses</em><em> </em>
Step-by-step explanation:
For the last part aka (6-1) just say that 6-1 is in parenthesis
Hope this helpss!! :DD♡
Step-by-step explanation:
By using Pythagoras theoram,
x²= (6)²+(4)²




optionD
The value of the discriminant for the quadratic equation –3 = –x2 + 2x is 16
<h3>What is the value of the discriminant for the
quadratic equation?</h3>
The quadratic equation is given as:
–3 = –x^2 + 2x
Rewrite the equation as:
x^2 - 2x - 3 = 0
A quadratic equation is represented as;
ax^2 + bx + c = 0
So, we have
a = 1
b = -2
c = -3
The discriminant is
d = b^2 - 4ac
So, we have
d = (-2)^2 - 4 * 1 * -3
Evaluate
d = 16
Hence, the value of the discriminant for the quadratic equation –3 = –x2 + 2x is 16
Read more about quadratic equation a
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The equation is equivalent to 1/cos(2x)-2=sin(2x)/cos(2x). Make the denominator cos(2x) for all terms, we get 1-2cos(2x)=sin(2x). Since cos^2(2x)+sin^2(2x)=1, let cos(2x)=a, substitute sin(2x) by +-\sqrt(1-a^2), and solve the equation with only one variable a. We get a=4/5 or 0, but cos(2x) cannot be 0, otherwise sec(2x) is undefined. 2x=36.9 degrees, so x=18.9 degrees approximately.

now, we know the tangent line at (2,4) is y = 8x - 12, now, that's already in slope-intercept form, so, the slope of that tangent at (2,4) is "8" then.
now, that means when x = 2, the slope is 8, so let's use that.