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sammy [17]
2 years ago
11

Solve the system of equations x=y+3 2x-3y=-3

Mathematics
1 answer:
Aloiza [94]2 years ago
5 0

Answer:

Step-by-step explanation:

hope this helps

sorry if didnt

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Write the words for the expression 3x(6-1)
fgiga [73]

Answer:

three <em>multipl</em><em>i</em><em>e</em><em>d</em><em> </em>by six <em>m</em><em>i</em><em>n</em><em>u</em><em>s</em><em> </em>one in <em>parentheses</em><em> </em>

Step-by-step explanation:

For the last part aka (6-1) just say that 6-1 is in parenthesis

Hope this helpss!! :DD♡

5 0
3 years ago
What is the value of x? Leave your answer in simplest radical form.
OleMash [197]

Step-by-step explanation:

By using Pythagoras theoram,

x²= (6)²+(4)²

{x}^{2}  = 36 + 16

{x}^{2}  = 52

x =  \sqrt{52}

x = 2 \sqrt{13}

optionD

5 0
3 years ago
Read 2 more answers
What is the value of the discriminant for the quadratic equation –3 = –x2 + 2x?
iogann1982 [59]

The value of the discriminant for the quadratic equation –3 = –x2 + 2x is  16

<h3>What is the value of the discriminant for the quadratic equation?</h3>

The quadratic equation is given as:

–3 = –x^2 + 2x

Rewrite the equation as:

x^2 - 2x - 3 = 0

A quadratic equation is represented as;

ax^2 + bx + c = 0

So, we have

a = 1

b = -2

c = -3

The discriminant is

d = b^2 - 4ac

So, we have

d = (-2)^2 - 4 * 1 * -3

Evaluate

d = 16

Hence, the value of the discriminant for the quadratic equation –3 = –x2 + 2x is  16

Read more about quadratic equation a

brainly.com/question/1214333

#SPJ1

4 0
2 years ago
Find all solutions in the interval [0, 2π).<br> sec2 x - 2 = tan2 x
maks197457 [2]
The equation is equivalent to 1/cos(2x)-2=sin(2x)/cos(2x). Make the denominator cos(2x) for all terms, we get 1-2cos(2x)=sin(2x). Since cos^2(2x)+sin^2(2x)=1, let cos(2x)=a, substitute sin(2x) by +-\sqrt(1-a^2), and solve the equation with only one variable a. We get a=4/5 or 0, but cos(2x) cannot be 0, otherwise sec(2x) is undefined. 2x=36.9 degrees, so x=18.9 degrees approximately.
3 0
3 years ago
Find the parabola with equation y = ax^2 + bx whose tangent line at (2, 4) has equation y = 8x − 12.
MrRissso [65]
\bf y=ax^2+bx\implies \cfrac{dy}{dx}=2ax+b

now, we know the tangent line at (2,4) is y = 8x - 12, now, that's already in slope-intercept form, so, the slope of that tangent at (2,4) is "8" then.

now, that means when x = 2, the slope is 8, so let's use that.

\bf \left. \cfrac{dy}{dx}  \right|_{x=2}\implies 2a(2)+b=\stackrel{\textit{from tangent equation}}{8}\implies 4a+b=8&#10;\\\\\\&#10;4a=8-b\implies a=\cfrac{8-b}{4}\implies \boxed{a=2-\cfrac{b}{4}}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;x=2\\&#10;y=4\\\\&#10;a=2-\cfrac{b}{4}&#10;\end{cases}\implies \stackrel{y = ax^2+bx}{4=\left( \boxed{2-\frac{b}{4}} \right)(2)^2+b(2)}\implies 4=8-b+2b&#10;\\\\\\&#10;\boxed{-4=b}\qquad thus\qquad a=2-\cfrac{-4}{4}\implies \boxed{a=3}\\\\&#10;-------------------------------\\\\&#10;y=3x^2-4x
5 0
3 years ago
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