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3 years ago

In right triangle ABC, B is the right triangle and m C = 30. If AC = 10 what is AB?

Mathematics

1 answer:

nekit [7.7K]3 years ago

4 0

Using the law of sins:

Sin(angle) = Opposite Leg / Hypotenuse

Sin(30) = AB /10

Solve for AB:

AB = 10 * sin(30)

AB = 10 * 1/2

AB = 5

The answer is A.

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PLEASE HELP!! 20 POINTS PLUS BRAINLIEST IF YOURE RIGHT!!

zaharov [31]

Firstly, we have to find the mean. The mean is simply the average of the numbers, which we find by adding each number in the sequence and then dividing that result by the total amount of numbers.

13.3 + 14.3 + 15.3 + 16.3 + 17.3 = 76.5

76.5 / 5 = 15.3

Okay, so our average is 15.3.

Now, we have to subtract the mean from each number and then square the result.

(13.3 - 15.3)^2 = 4
(14.3 - 15.3)^2 = 1
(15.3 - 15.3)^2 = 0
(16.3 - 15.3)^2 = 1
(17.3 - 15.3)^2 = 4

Now we have to find the mean of those numbers!

4 + 1 + 0 + 1 + 4 = 10

10 / 2 = 2

Finally, we take the square root of that number and we have our standard deviation. =)

8 0

3 years ago

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

The expression can no longer be simplified

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

3 years ago

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The diagonal of a square is 8 cm.

VladimirAG [237]

the length of the side of this square is $4\sqrt{2} \:or \:5.65$ cm

Answer:

Solutions Given:

let diagonal of square be AC: 8 cm

let each side be a.

As diagonal bisect square.

let it forms right angled triangle ABC .

Where diagonal AC is hypotenuse and a is their opposite side and base.

By using Pythagoras law

hypotenuse ²=opposite side²+base side²

8²=a²+a²

64=2a²

a²= $\frac{64}{2}$

a²=32

doing square root on both side

$\sqrt{a²}=\sqrt{32}$

a=± $\sqrt{2*2*2*2*2}$

a=±2*2 $\sqrt{2}$

Since side of square is always positive so

a=4 $\sqrt{2}$ or 5.65 cm

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3 years ago

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Find a primitivism root of 6

avanturin [10]

Answer:

6, 5, 47, 5, 103, 5, 167, 5

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3 years ago

What’s 2 plus 2 Pupil:4 That’s good Good?, that’s perfect!

Lesechka [4]

Answer:

Step-by-step explanation:

2+2=4

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3 years ago

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