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2 years ago

What is the equation that is perpendicular to the line y=2x-3 and passes through the point (-6,5)? Show all of your work.

Mathematics

1 answer:

Helga [31]2 years ago

5 0

Answer:

y = m x + b equation for a straight line

m m' = -1 for perpendicular lines

Thus m' = -1/2 is required

Check:

-1/2 * -6 + 2 = = 3 + 2 = 5 = y for the last equation give

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Find the inverse of the given relation. {(9, –14), (–7, 4), (6, –8)}

Law Incorporation [45]

Answer:

{(-14,9),(4,-7),(-8,6)}.

Step-by-step explanation:

To find the inverse you just swap x and y.

So if (a,b) is a point on the relation then (b,a) is on it's inverse.

So the inverse of {(9, –14), (–7, 4), (6, –8)} is:

{(-14,9),(4,-7),(-8,6)}.

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3 years ago

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2 years ago

Which of the following is equal to the expression listed below?

Novay_Z [31]

Answer:

Step-by-step explanation:

9(5 + 2)

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3 years ago

Help subtract (xsquared +43x10)-(10xsquared-5x+10 express the answer in standard form

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Answer:

$\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}$

Step-by-step explanation:

$(x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x$

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3 years ago

How do i solve this? 7 < 3 - 2x It's linear inequalities

Natasha2012 [34]

Hello from MrBillDoesMath!

Answer:

x < -2

Discussion:

7 < 3 - 2x => Add 2x to both sides

7 + 2x < 3 - (2x - 2x) => As 2x -2x = 0

7 + 2x < 3 => Subtract 7 from both sides

(7-7) + 2x < 3 - 7 => As 7-7 = 0 and 3-7 = -4

2x < -4 => Divide both sides by 2

x < -4./2 = -2

Thank you,

MrB

7 0

3 years ago