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3 years ago

7

On Monday it rained two and one-half inches. On Tuesday it rained three and three-fourths inches. How much did it rain in the tw

o days?

1 answer:

charle [14.2K]3 years ago

3 0

Answer:

it rained 6 1/4 or 6.25 inches in two days

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From a random sample of workers at a large corporation you find that 58% of 200 went on a vacation last year away from home for

vagabundo [1.1K]

Answer:

b. We are 95% confident that the proportion of coworkers who went on a vacation last year away from home for at least a week is between 50% and 66%.

Step-by-step explanation:

A confidence interval at the level of x% for a proportion being between a and b means that we are x% sure that the true proportion of the population is between a and b.

In this problem, we have that:

95% C.I is (0.5, 0.66)

Interpretation: 95% confident that the true proportion is between 0.5 and 0.66.

The correct answer is:

b. We are 95% confident that the proportion of coworkers who went on a vacation last year away from home for at least a week is between 50% and 66%.

6 0

3 years ago

4×9×8^-1×3^-3/6^-1 .Ans is 1 but I want the method.

lana66690 [7]

Answer:

Hi, Hope this will help :-)

5 0

3 years ago

Read 2 more answers

How to write a real world problem involving the subtraction of two mixed numbers whose difference is less than 2 1/2

madreJ [45]

You can do 2 1/2 minus 1 1/8 to get 1 3/8. Your welcome and I hope you get a good grade

7 0

3 years ago

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

3 years ago

−20≤59(F−32)≤−15 please i need help<br><br> v+8 <3v+8 <3 or −8v<−40−8v<−40<br><br> 6

ozzi

The answer is -148≤ F≤ -103!

6 0

3 years ago