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3 years ago

7

On Monday it rained two and one-half inches. On Tuesday it rained three and three-fourths inches. How much did it rain in the tw

o days?

1 answer:

charle [14.2K]3 years ago

3 0

Answer:

it rained 6 1/4 or 6.25 inches in two days

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Given b(x)=|x+41|, what is b(-10)?

Montano1993 [528]

Answer:

31

Step-by-step explanation:

Substitute -10 for x in b(x)=|x+41|, obtaining f(-10) = |-10 + 41|. This result simplifies to f(-10) = |31| = 31

6 0

2 years ago

The University of Southern California is located about 2.5 miles west and about 2.8 miles south of downtown Los Angeles. Suppose

Jlenok [28]

If x represents distance measured east of downtown, and y represents distance measured north of downtown, the circle of radius 40 centered at (-2.5, -2.8) will have an equation of the form
(x - h)² + (y - k)² = r²
where the center is (h, k) and the radius is r. The locus of points 4 miles from USC will satisfy the equation
(x +2.5)² + (y + 2.8)² = 1600

3 0

3 years ago

Which function represents the graph of h(x)=2|x+3|−1 after it is translated 2 units right?

harina [27]

$\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}$

$\bf ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}$

$\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}$

now with that template in mind

$\bf h(x)=\stackrel{A}{2}|\stackrel{B}{1}x+\stackrel{C}{3}|\stackrel{D}{-1}\qquad \qquad \stackrel{\textit{C=C-2 a translation to the right}}{h(x)=2|x\boxed{+3-2}|-1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill h(x)=2|x+1|-1~\hfill$

8 0

3 years ago

Read 2 more answers

In ΔRST, s = 70 inches, t = 46 inches and ∠R=109°. Find ∠T, to the nearest degree.

gayaneshka [121]

Answer:

72 degrees

Step-by-step explanation:

Delta Math

3 0

3 years ago

Find the second derivative at the point (2,2), given the function below. 2x^4=4y^3

Bogdan [553]

The second derivative at the point (2,2) is 34/9

<u>Explanation:</u>

<u></u>

2x⁴ = 4y³

2x⁴ - 4y³ = 0

We first need to find dy/dx and then d²y/dx²

On differentiating the equation in terms of x

dy/dx = d(2x⁴ - 4y³) / dx

We get,

dy/dx = 2x³/3y²

On differentiating dy/dx we get,

d²y/dx² = 2x²/y² + 8x⁶/9y⁵

$\frac{d^2y}{dx^2} = \frac{2 X 2^2}{2^2} + \frac{8 X 2^6}{9 X 2^5}\\ \\\frac{d^2y}{dx^2} = 2 + \frac{16}{9}\\ \\$

d²y/dx² = 34/9

Therefore, the second derivative at the point (2,2) is 34/9

7 0

3 years ago