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densk [106]
3 years ago
15

When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?

Mathematics
2 answers:
Radda [10]3 years ago
5 0
The correct answer for this question is this one: "B. increase your scale values"

<span>When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by </span><em>increasing your scale values</em>
Hope this helps answer your question and have a nice day ahead.
Arada [10]3 years ago
5 0

Answer:

Option: B is correct.

B) Increase your scale values.

Step-by-step explanation:

When creating a scatterplot, if the points are too close together to see the relationship,then we must increase the scale value of our graph .

"  Because by doing so the point will seem to be farther and we could see the clear relationship between the points and hence it will not create any confusion regarding the visual of the points and hence easily the inference could be drawn"

Hence, option: B is true.

(B) Increase the scale value)

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Calculate the pay for the following day of a weekly time card given a wage of $14/hr
xxTIMURxx [149]

Answer: $122.50

Step-by-step explanation:

We know the difference between the time the employee clocked in and clocked out = 1200 - 0800 = 4 hours

The next clock in and out = 17:30 - 12:45 = 4 hours, 45 minutes.

These times combined = 8 hours, 45 minutes

\frac{45}{60} minutes in an hour = \frac{3}{4} of an hour.

The total time worked was 8 \frac{3}{4} hours.

Multiply 8.75 × $14 = $122.50

I am not a professional, simply using prior knowledge.

Note- it would mean the world to me if you could mark me brainliest!

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3 years ago
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2 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
3 years ago
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