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choli [55]
3 years ago
15

What is the domain of the function? Enter your answer in the box below.

Mathematics
1 answer:
Kay [80]3 years ago
7 0

Answer:

The domain is the value of x for which the function is defined

Domain={x|-6≤x≤8}

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Which of the following graphs represents the equation below?: -9x – 3y = -8
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It’s C! that’s the answer, hope it helps
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A musical instrument has a pitch of 220 hertz when the wavelength is 3 feet. When the wavelength is 4 feet, the pitch is 165 her
earnstyle [38]
We know that
Inverse Variation is a<span> relationship between two variables in which the product is a constant
so
let
x------> a pitch of a musical instrument
y------> </span><span>the wavelength
x*y=k

find the value of k

for x=</span><span>220 hertz   y=3 ft
</span><span>x*y=k
220*3=k
k=660

</span>for x=165 hertz   y=4 ft
x*y=k
165*4=660
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the answer part a) is
</span><span>the type of variation between pitch and wavelength is an inverse variation
</span>
part b) <span>What is the pitch when the wavelength is 5 feet?
x=?
y=5 ft
k=660
x*y=k------> solve for x
x=k/y----------> x=660/5-----> x=132 hertz

the answer Part b) is
132 hertz</span>
4 0
3 years ago
A worker is being raised in a bucket lift at a constant speed of 3 ft/s. When the worker's arms are 10 ft off the ground, her co
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Read 2 more answers
How many temperature in Biratnagar​
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Answer:

Step-by-step explanation:

do you mean "what is the temperature in birantnager?"

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6 0
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Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv
AnnZ [28]

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

\Delta Sector=\dfrac{1}{2}r^2\theta

Whereas the area of a circle for a radius r is given as

\Delta Circle=\pi r^2

Now the ratio is given as

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

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