The relationship between Sabir and calories he burns can be modeled using a linear function given by:
y=ax+b
where
a=slope
b=y-intercept
from the graph, the slope will be given as follows:
taking points (3,15) and (12,60)
a=(60-15)/(12-3)=5 calories/minute
thus using the slope and a point (3,15) the equation will be:
a(x1-x)=(y1-y)
plugging the values we obtain:
5(x-3)=y-15
5x-15=y-15
thus
y=5x
thus the equation is:
y=5x
Answer y=25/3 or 8.33333 and x=0.4444443
Step-by-step explanation:
y=4(y-7/3)+3 y=4y-28+3 y=4y-25
The key idea here is that
speed of plane in wind = (speed of plane in air) + (speed of wind)
Let
be the speed of the plane in still air, and
the wind speed. A tailwind blows in the same direction as the plane, so for the first leg of the trip, we have

For the return trip, the wind would blow in the opposite direction:

Solve this system and you'll find
and
.