2 years ago

The valley was at least 4 feet below sea level. Inequality? PLEASE HELP DUE TODAY!!!!

1 answer:

3 0

If you are given t<span>he valley of at least 4 feet below sea level, and then let us assume that x is the distance of the valley, then the inequality is x < 4. </span>

You might be interested in

Can someone please help me with these two questions?

Anna71 [15]

10. 4,200 cm
This is the correct answer!

3 0

2 years ago

Read 2 more answers

Simplify <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%2036" id="TexFormula1" title="x^{2} - 36" alt="x^{2} - 36" align="abs

Alexxandr [17]

Answer:

${x}^{2} - 36 \\ = (x + 6)(x - 6)$

Step-by-step explanation:

x^2-36

(x+6) ( x-6)

it's helpful to you

6 0

2 years ago

Read 2 more answers

If P = h+r, then h = . what is the answer?

Elan Coil [88]

Answer:

h = P - r

Step-by-step explanation:

Given

P = h + r ( isolate h by subtracting r from both sides )

P - r = h

5 0

2 years ago

Read 2 more answers

ASAP please it’s very important

zaharov [31]

Answer:

x = 30° and 330°

Step-by-step explanation:

Assuming the intervals is {0 , 2π} or {0° , 360°}

$tan\ x=\frac{-\sqrt{3} }{3} \\\\x=tan^{-1} (\frac{-\sqrt{3} }{3})\\\\x = -30$

So it means it lies in the 2nd and 4th quadrant because tangent is negative in the 2nd and 4th quadrant

so the two solutions are

x = 30° and 330° or

$x=\frac{\pi }{6}\ radians\ \ , \ \ \frac{11\pi }{6}\ radians$

4 0

2 years ago

Let θ (in radians) be an acute angle in a right triangle, and let x and y, respectively, be the lengths of the sides adjacent an

Fed [463]

Explanation is given step by step just below:
tan(theta(t))=y(t)/x(t)

differentiate
sec^2(theta(t))*theta'(t)=y'(t)x(t)-y(t)x'(t)/x^2(t)
thus
theta'(t)=(y'(t)x(t)-y(t)x'(t))
divided by (x^2(t)*sec^2(θ(t))

8 0

2 years ago

Read 2 more answers