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3 years ago

What is the upper quartile of this data set? 82, 97, 98, 100, 102, 102, 106, 112

Mathematics

2 answers:

snow_lady [41]3 years ago

7 0

Answer:

104

Step-by-step explanation:

The upper quartile is the median of the upper half of the data set, and that is 104.

vova2212 [387]3 years ago

3 0

Answer:

104

Step-by-step explanation:

In this set data set (82, 97, 98, 100, 102, 102, 106, 112) the median is 101

This means that the upper quartile is 104

To find the upper quartile, you take the numbers that come after the median, and find the median of that set. So when finding the upper quartile of this data set, you will only look at the numbers 102, 102, 106, 112, and the median of this is 104.

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Sunny_sXe [5.5K]

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Step-by-step explanation:

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3 years ago

What is the solution set of x2 + 5x + 1 = 0?

DerKrebs [107]

Answer:

$\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}$

Step-by-step explanation:

$x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}$

$\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}$

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