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ICE Princess25 [194]
3 years ago
12

What is the upper quartile of this data set? 82, 97, 98, 100, 102, 102, 106, 112

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0

Answer:

104

Step-by-step explanation:

The upper quartile is the median of the upper half of the data set, and that is 104.

:)

vova2212 [387]3 years ago
3 0

Answer:

104

Step-by-step explanation:

In this set data set (82, 97, 98, 100, 102, 102, 106, 112) the median is 101

This means that the upper quartile is 104

To find the upper quartile, you take the numbers that come after the median, and find the median of that set. So when finding the upper quartile of this data set, you will only look at the numbers 102, 102, 106, 112, and the median of this is 104.

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Step-by-step explanation:

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3 years ago
Use the sum and difference identities to find the exact values of the sine, cosine, and tangent of the angle. . 165 = 135 + 30
Serhud [2]
So lets get to the problem 

<span>165°= 135° +30° </span>

<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>

<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
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<span>= Cos45°Cos30° - Sin45°Sin30° </span>

<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>


<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>

<span>Substitute the above values with the following... These should be memorized </span>
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<span>Cos 30° =[Sqrt(3)]/2 </span>
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<span>Tan 45° = 1</span>
4 0
3 years ago
Have another question for you guys it is in the image
Lerok [7]

Answer:

A because its supposed to be on the y axis

5 0
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