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Maurinko [17]
3 years ago
6

Translation: I unit left and 2 units up

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Just shift every point 2 units up and 1 unit left, then connect the dots.

Mazyrski [523]3 years ago
5 0
(X,Y)—-> (X-1, Y+2) left goes negative and up is positive
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Lucas makes a flag it has 6 equal parts five of the parts are red what fraction of the flag is red
deff fn [24]
One part of six parts is red, so just make it a fraction like so: 1/6 because 1 side is red out of six total parts.
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3 years ago
How many pairs of opposite sides are parallel? no pairs 1 pair 2 pairs Submit​
Naddika [18.5K]

Answer:

no pairs

Step-by-step explanation:

no pairs are equal and they all intersect at a point

5 0
3 years ago
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Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript one-fourth x?
Nat2105 [25]
<h3>Answer: Choice C</h3>

RootIndex 12 StartRoot 8 EndRoot Superscript x

12th root of 8^x = (12th root of 8)^x

\sqrt[12]{8^{x}} = \left(\sqrt[12]{8}\right)^{x}

=========================================

Explanation:

The general rule is

\sqrt[n]{x} = x^{1/n}

so any nth root is the same as having a fractional exponent 1/n.

Using that rule we can say the cube root of 8 is equivalent to 8^(1/3)

\sqrt[3]{8} = 8^{1/3}

-----

Raising this to the power of (1/4)x will have us multiply the exponents of 1/3 and (1/4)x like so

(1/3)*(1/4)x = (1/12)x

In other words,

\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/3)*(1/4)x}

\left(8^{1/3}\right)^{(1/4)x} = 8^{(1/12)x}

-----

From here, we rewrite the fractional exponent 1/12 as a 12th root. which leads us to this

8^{(1/12)x} = \sqrt[12]{8^{x}}

8^{(1/12)x} = \left(\sqrt[12]{8}\right)^{x}

4 0
3 years ago
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sergejj [24]

Answer:

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1        | 2.5

2       | 5

3       | 7.5

4       | 10

Goes up by 2.5 each time

Not sure if this is what you want

Step-by-step explanation:

equation is y = 2.5x

4 0
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What is the area of the polygon in square units?<br> Correct answer gets brainliest
givi [52]

Answer:

72

Step-by-step explanation:

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3 years ago
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