Since 10 is a positive the opposite must be negative. Opposite integer of 10 is -10 ( negative 10).
Happy studying ^-^
Sorry in order to answer this I need the picture of the 4 triangles
Answer:
Step-by-step explanation:
Let the solution to
2x^2 + x -1 =0
x^2+ (1/2)x -(1/2)
are a and b
Hence a + b = -(1/2) ( minus the coefficient of x )
ab = -1/2 (the constant)
A. We want to have an equation where the roots are a +5 and b+5.
Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.
The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.
So the equation is
x^2-(19/2)x + 22 =0
2x^2-19x + 44 =0
B. We want the roots to be 3a and 3b.
Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and
(3a)(3b) = 9(ab) =9(-1/2)=-9/2.
So the equation is
x^2 +(3/2) x -9/2 = 0
2x^2 + 3x -9 =0.
Answer:
x = -26 and y = -2
I hope this is the answer you are looking for
Step-by-step explanation:
x-8y = -10 => add 8y to both sides
+8y = +8y
x = -10+8y
-2(-10+8y) -6y = -24 => intersect what you got into the first equation
20-16y-6y = -24 => Distribute the -2
20-22y = -24 => subtract 20 in both sides
-20 = -20
-22y = -44 => divided by -22 in both sides
/-22 = /-22
y = -2
x-8(-2) =-10 => intersect the y into the other equation
x+16 = -10 => multiply -8*-2
-16 = -16
x = -26 => subtract 16 in both sides.
