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2 years ago

A student catches a can of soda dropped from some unknown height by Mr. Fineman. If

Physics

1 answer:

nikdorinn [45]2 years ago

3 0

Answer:

v² = u² + 2gh

8.9² = 0² + 2(9.8)h

h = 4.0 m

v = at

t = 8.9/9.8

t = 0.91 s

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A parallel-plate capacitor is constructed of two square plates, size L×L, separated by distance d. The plates are given charge ±

gladu [14]

Answer:

E(final)/E(initial)=2

Explanation:

Applying the law of gauss to two parallel plates with charge density equal σ:

$E=\sigma/\epsilon_{o}=Q/(L^{2}*\epsilon_{o})\\$

So, if the charge is doubled the Electric field is doubled too

E(final)/E(initial)=2

3 0

3 years ago

A train travels up a hill that is 100 meters long. If the train has climbed 50 meters vertically. How far the train traveled hor

NeTakaya

Answer:

27.3 meters

Explanation:

A train travels up a hill that is 100 meters long. If the train has climbed 50 meters vertically, it traveled 27.3 meters vertically. Therefore, the answer is 27.3 meters.

(100)² = (50)²+x²

10000 - 2500 = x²

7500 = x²

x = 27.3 or 27.3 meters

Hope this helped!

4 0

3 years ago

Which of the following determines and objects ability to float in water

AleksandrR [38]

I think its
Mass and volume

6 0

3 years ago

a 200 kg crate is pushed horizontally with a force of 700 N. If the coefficient of friction is 0.2 calculate the acceleration of

Crazy boy [7]

Answer:

$a=1.54\ m/s^2$

Explanation:

<u>Net Force</u>

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

That acceleration is proportional to the net force and inversely proportional to the mass of the object.

It can be expressed with the formula:

$\displaystyle a=\frac{F_n}{m}$

Where

Fn = Net force

m = mass

The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes motion and a horizontal net force appears causing the acceleration.

The forces on the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal:

N = W = mg

The friction force can be calculated by using the coefficient of friction μ:

$F_r=\mu N$