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MA_775_DIABLO [31]
2 years ago
5

How many planets are in our Solar system? I'll give brainliest

Physics
1 answer:
Dima020 [189]2 years ago
8 0

Answer:

The following is Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune

That is from our solar system

Explanation:

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Trava [24]

Answer:

2

Explanation:

6 0
3 years ago
Why are the orbits of planets only nearly circular and not perfectly circular?
Galina-37 [17]

Explanation:

this is my answer this is helpful for you

7 0
2 years ago
What does the area between the line and the x-axis represent on a velocity vs. time graph?
Finger [1]

Answer:

It has been learned in this lesson that the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period. ... Once calculated, this area represents the displacement of the object.

Explanation:

7 0
3 years ago
Read 2 more answers
What does keplers second law of planetary monition imply
Gemiola [76]
Kepler's second law of planetary motion<span> describes the speed of a </span>planet<span> traveling in an elliptical orbit around the sun. It states that a line between the sun and the </span>planetsweeps equal areas in equal times. Thus, the speed of theplanet<span> increases as it nears the sun and decreases as it recedes from the sun.</span>
6 0
3 years ago
Read 2 more answers
A beam of light, with a wavelength of 4170 Å, is shined on sodium, which has a work function (binding energy) of 4.41 × 10 –19 J
Lyrx [107]

Explanation:

Given that,

Wavelength of the light, \lambda=4170\ A=4170\times 10^{-10}\ m

Work function of sodium, W_o=4.41\times 10^{-19}\ J

The kinetic energy of the ejected electron in terms of work function is given by :

KE=h\dfrac{c}{\lambda}-W_o\\\\KE=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{4170\times 10^{-10}}-4.41\times 10^{-19}\\\\KE=3.59\times 10^{-20}\ J

The formula of kinetic energy is given by :

KE=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2KE}{m}} \\\\v=\sqrt{\dfrac{2\times 3.59\times 10^{-20}}{9.1\times 10^{-31}}} \\\\v=2.8\times 10^5\ m/s

Hence, this is the required solution.

7 0
3 years ago
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