Answer:
2 and -3
Step-by-step explanation:
Let the numbers be x and y ∴ 4x -2y =-16......................Eqn 1
and x+y=-1.................................Eqn 2
this ⇒x=-1-y. Substitute the value of x to be=-1 -y and putting in Eqn 1 yields the following 4(-1-y)-2y =-16 0r -4-4y-2y=-16
⇒-4-6y=-16 0r =-6y=-12 ∴y is 2
⇒ and x is -3
I think the answer is 36 tin because e the radius is 4
Answer:
(-1, -1) Let me know if the explanation didn't make sense.
Step-by-step explanation:
If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left. This means M is only connected to N here and P is only connected to N. So we want to find the slope of these two lines.
MN is easy since their y values are the same, the slope is 0.
NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.
So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0. To find these lines weuse point slope form for those two points. The formula for point slope form is y - y1 = m(x-x1)
y-3 = -4(x+2) -> y = -4x-5
y+1 = 0(x-5) -> y = -1
So now we want these two to intersect. We just set them equal to each other.
-1 = -4x -5 -> -1 = x
So this gives us our x value. Now we can plug that into either function to find the y value. This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)
