Answer:
The answer is "3".
Step-by-step explanation:
If the compression factor of 3 is modified, the k value is 3 For a function f(x) the horizontal extending or compression is provided by g = f (bx)
Here b is constant. Where b is constant.
If b> 0, the function graph is condensed. The fact that perhaps the function is transformed by an encoding factor of 3 is given in the question.
Answer:
Grade A:
Grade B:
Grade C:
Grade D:
Step-by-step explanation:
Problems of normally distributed samples can be solved using the Z score table.
The Z score of a measure represents how many standard deviations it is above or below the mean of all the measures.
Each Z score has a pvalue. This represents the percentile of the measure.
In this problem, we have that:
The upper 16% of the class get A grades. The upper 16% has a pvalue of at least 100% = 16% = 84% = 0.84. This is .
The middle 34% of the class get B grades. The middle 34% has a pvalue of at least 84%-35% = 50% = 0.5 and at most 0.84. This is .
Those between a pvalue of 0.5-0.34 = 0.16 and 0.5 get get grade C. has a pvalue of 0.16. So a grade C is in the interval
.
Those with Z lesser than -1 get grades D and F
Answer:
t = - 24
Step-by-step explanation:
Given t varies inversely as a then the equation relating them is
t = ← k is the constant of variation
To find k use the condition t = 2 when a = - 4
2 = ( multiply both sides by - 4 )
- 8 = k
t = ← equation of variation
When a = , then
t = = - 24