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Rus_ich [418]
3 years ago
12

Grades in large classes are sometimes approximately Normally distributed—a fact that serves as the justification for "grading on

a bell curve." A common practice for very large classes is to give 16% of students A grades, 34% B grades, 34% C grades, and 16% D and F grades. Assuming a Normal distribution of grades, what are the z-scores for these letter grades?
Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:

Grade A: Z \geq 1

Grade B: 0 \leq Z < 1

Grade C: -1 \leq Z < 0

Grade D: Z < -1

Step-by-step explanation:

Problems of normally distributed samples can be solved using the Z score table.

The Z score of a measure represents how many standard deviations it is above or below the mean of all the measures.

Each Z score has a pvalue. This represents the percentile of the measure.

In this problem, we have that:

The upper 16% of the class get A grades. The upper 16% has a pvalue of at least 100% = 16% = 84% = 0.84. This is Z \geq 1.

The middle 34% of the class get B grades. The middle 34% has a pvalue of at least 84%-35% = 50% = 0.5 and at most 0.84. This is 0\leqZ < 1.

Those between a pvalue of 0.5-0.34 = 0.16 and 0.5 get get grade C. Z = -1 has a pvalue of 0.16. So a grade C is in the interval -1 \leq Z < 0.

Those with Z lesser than -1 get grades D and F

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NO LINKS!!! Please help me with these problems​
nadezda [96]
<h3>Answers:</h3>

7) Center= (-1,2) Radius= \boldsymbol{\sqrt{8}} Equation: (x+1)^2+(y-2)^2 = 8

8) Center= (3,13) Radius= 13 Equation: (x-3)^2+(y-13)^2 = 169

=========================================================

Explanation:

Problem 7

Let's find the distance from (-1,2) to (-3,4)

(x_1,y_1) = (-1,2) \text{ and } (x_2, y_2) = (-3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-3))^2 + (2-4)^2}\\\\d = \sqrt{(-1+3)^2 + (2-4)^2}\\\\d = \sqrt{(2)^2 + (-2)^2}\\\\d = \sqrt{4 + 4}\\\\d = \sqrt{8}\\\\

This is the radius because it stretches from the center to a point on the circle, so r = \sqrt{8}

Squaring both sides will get us r^2 = 8

One useful template for a circle is the equation (x-h)^2+(y-k)^2 = r^2\\\\

(h,k) is the center

r is the radius

Let's plug in the given center (h,k) = (-1,2) and the r^2 value we found earlier.

(x-h)^2+(y-k)^2 = r^2\\\\(x-(-1))^2+(y-2)^2 = 8\\\\(x+1)^2+(y-2)^2 = 8\\\\

You can confirm this by using a tool like Desmos. See below.

------------------------------------------------------------------------

Problem 8

The endpoints of the diameter are (-2,1) and (8,25)

The center is the midpoint of these endpoints.

The midpoint of the x coordinates is (-2+8)/2 = 3

The midpoint of the y coordinates is (1+25)/2 = 13

The center is (h,k) = (3,13)

Now find the distance from the center to one of the points on the circle, let's say to (8,25)

(x_1,y_1) = (3,13) \text{ and } (x_2, y_2) = (8,25)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-8)^2 + (13-25)^2}\\\\d = \sqrt{(-5)^2 + (-12)^2}\\\\d = \sqrt{25 + 144}\\\\d = \sqrt{169}\\\\d = 13\\\\

The radius is exactly 13 units.

So,

(x-h)^2+(y-k)^2 = r^2\\\\(x-3)^2+(y-13)^2 = 13^2\\\\(x-3)^2+(y-13)^2 = 169\\\\

is the equation of this particular circle.

Visual confirmation is shown below.

8 0
3 years ago
Read 2 more answers
Which statements are true for verifying the solution set of StartAbsoluteValue negative 2 x + 8 EndAbsoluteValue less-than 12 as
mariarad [96]

Answer:

I had to go back and double check, this was kind of confusing asking if  saying this statement is true or false is true or false.  So keep your eye on that.  as long as x is between (but not equal to) -2 and 10 then the inequality is true.  Fromt here you have to see if the option is SAYING it is true or not.

Step-by-step explanation:

I am assuming this is saying |-2x+8|<12 as -2 < x < 10

Substituting 10 for x into the original inequality will create a false statement.

True, since x has to be explicitly LESS THAN 10, not equal

Substituting 6 for x into the original inequality will create a false statement.

False, 6 is greater than -2 and less than 10

Substituting 20 for x into the original inequality will create a true statement.

False, greater than 10

Substituting –20 for x into the original inequality will create a false statement.

True.  Kinda confusing since it is asking if it is a false statement.  It is TRUE that it is a false statement.

Substituting –10 for x into the original inequality will create a true statement.

False, x needs to be between -2 and 10 (explicitly between and not equal to) to be true.  

Substituting 0 for x into the original inequality will create a true statement

True, it is between -2 and 10

8 0
3 years ago
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Barry Road his scooter<br> for 24 minutes at a speed of 0.5 per minute how far did he go
liraira [26]
Well, I'm not sure what units "0.5" apply to, but to find the distance he rode, you will need to multiply.

0.5 * 24 = 12.

Barry rode his scooter for a distance of 12 [insert units here].

Hope this helps! Have a great day :)
7 0
3 years ago
How should the decimal point in 948.921 change to get the correct answer to 948.921 ÷ 10 to the power of 4?
k0ka [10]

Answer:

move it 4 places to the left

Step-by-step explanation:

10 to 4th power is basically 10000 so 948.921 divided by 10000 so its obvious it will not move to the right, making the number bigger.

8 0
3 years ago
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1. Define sets
Rudik [331]

Answer:

  • Set is a collection of specified object.
  • The types of set are Finite Set. A set which contains a definite number of elements is called a finite set. ...

Infinite Set. A set which contains infinite number of elements is called an infinite set. ...

Subset. ...

Proper Subset. ...

Universal Set. ...

Empty Set or Null Set. ...

Singleton Set or Unit Set. ...

Equal Set.

  • The operation used on sets are. 1 Intersection 2.Union 3.Difference 4.Compelement

4 0
3 years ago
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