Given the function f (x) = 3x — 2, what is the value of f (3)?

Mathematics

1 answer:

Ne4ueva [31]2 years ago

6 0

Answer:

Step-by-step explanation:

Simply plug in 3 for x. 3 times 3 is 9 and 9 minus 2 is 7.

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Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

8 0

2 years ago

Equivalent expression for 7a+21

Mila [183]

Answer:

Step-by-step explanation:

If you factor the expression 7a+21 you can get:

7 × (a+3)

6 0

3 years ago

Correct position in the answer box. Releast your

Aloiza [94]

The equation of the line is y=6x+37

Step-by-step explanation:

You can write the equation using the slope intercept form techniques which is y=mx+c where m is the slope of the line and cis they intercept constant.

Given the point (-6,1) and slope m=6then

Δy/Δx =m

$y-1/x--6 = 6\\\\y-1/x+6=6\\\\\\y-1=6(x+6)\\\\\\y-1=6x+36\\\\\\y=6x+36+1\\\\y=6x+37$