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Artyom0805 [142]
3 years ago
9

MONEY Sadie has $22.75 in her school lunch account. If she wants the money to last for this 5-day week of school, determine the

appropriate
amount she should spend each day. $________?
I’m confused
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

The most she can use in a day is $4.55.

Step-by-step explanation:

The explanation is simple.

22.75 divided by 5 = 4.55

Mark as Brainliest!

hjlf3 years ago
4 0

Answer:

$4.55

Step-by-step explanation:

All you do is take the total amount Sadie has right now and divide it by how many days it needs to last.

$22.75/5=$4.55

So Sadie can only spend $$.55 a day for the 5 days.

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Suppose there are two types of tickets to a show: advance and same day. The combined cost of one advance ticket and one same day
Debora [2.8K]

Answer:

Answer = $30.00 advanced and $36.00 same day.

Step-by-step explanation: We can replace 20:40 ratio.

30 x 20 and 70 x 20 = 600+ 800 =3/5  to find 2/4 = 12/20 finds 10/20 through HCF and hereafter we have one ticket is 1/6 more. So if 60 tickets were sold for 2000 then $33.33 would be the average and if one was 1/6 more than the other it is 0.5/6 higher than 33.33 =2.66 more = £36 for All day and £30 for Advanced tickets. 36 x 20 = $600  and 36 x 40 =$1400. We know its $30 as we can double check its ratio after. 20:40 is 1/2 but then take off $3 each side to balance back to find $60 combined. $2000=1400+$600 =1:2 and 2:4 ratio.

5 0
3 years ago
Does this table represent a function? Why or why not
skad [1K]

Answer: D) Yes, because each x value corresponds to exactly one y value

The table doesn't mention x, but usually x is in the left column. Since we don't have any repeated x values here, this means each input goes to exactly one output. So we have a function.

Visually if you plotted all the points, you'll see the graph passes the vertical line test.

7 0
3 years ago
Helppppppppppppppppp​
Darina [25.2K]

Answer:

3)

Step-by-step explanation:

An equation is linear if equal changes in x produce equal changes in y.

Let's look at each choice.

1)

A decrease of 10% per year. That means each year, the value of the car is 0.9 times the value of the previous year.

For example, if the original value was $10,000, after 1 year, it is worth 0.9 * $10,000 = $9,000. In 1 year it lost $1,000. In the next year, its value is now 0.9 * $9,000. The value at the end of the 2nd year is $8,100. In the second year, it lost $900 in value. In one period of 1 year it lost $1000 in value. In another equal period of 1 year, it lost $900 in value. A change of 1 year in time produces different changes in loss of value, so it is not linear.

2)

Here, the number doubles every year. Let's say it starts with 100 fish. After 5 years, it has 200 fish. In a change of 5 years in x, the change in y is 100. In the next 5 years, it goes from 200 fish to 400 fish. The change in the second period of 5 years is 200. We see that a change of 5 years can produce a change of 100 fish, but another change of 5 years can produce a change is 100 fish. Since for equal changes in x, the changes in y are not all equal, this is not linear.

3)

Here for every change of 1 day in x, the change in y is 2 liters. Each change of 1 in x always produces a change of 2 in y. This is linear.

4)

Each 2 hours, the amount of caffeine is 2/3 of what it was before. This is similar to the choice 1), and it is not linear.

Answer: 3)

7 0
3 years ago
The population at a football stadium is 4,068 people.The ratio of men to women in the stadium is 5:4.How many women are at the s
saveliy_v [14]
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ 5 + 4 = 9

4068/9 = 452

4 x 452 = 1808

There are 1808 woman at the stadium

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ <u>ʜᴀɴɴᴀʜ</u> ♡

4 0
4 years ago
Match with correct description
fgiga [73]
First one:  If the leading coeff. is negative, the graph begins in Quadrant III and ends in Quadrant IV.  It's an even function.   The fourth graph represents it.

If the leading coeff. is positive, but everything else remains the same, the graph opens upward, beginning in Q II and ending in Q I.

8 0
3 years ago
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