Question

Could someone pls help me out ???

Answer 1

Answer:

Option C.

Step-by-step explanation:

$\sf\:x^{2}-3x+7=0$

Use the biquadratic formula.

$\sf\:\x=\frac{-\left(-3\right)(+/-)\sqrt{\left(-3\right)^{2}-4\times 7}}{2}$

$\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{9-4\times 7}}{2}$

$\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{9-28}}{2}$

$\sf\:x=\frac{-\left(-3\right)(+/-)\sqrt{-19}}{2}$

$\sf\:x=\frac{3(+/-)\sqrt{19}}{2}$

Positive sign:

$\boxed{\sf\:x=\frac{3+\sqrt{19}}{2}}$

Negative sign:

$\boxed{\sf\:x=\frac{3-\sqrt{19}}{2}}$

Hope it helps ⚜