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3 years ago

In the number 8,825, how do the two 8s compare?

Mathematics

1 answer:

den301095 [7]3 years ago

7 0

Answer:

the 8 on the left is 10 times the value of the 8 on the right

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Sam is looking for a cell phone plans.A local company offers a monthly plan for $58.95. The company is having a sale and offerin

AysviL [449]

Answer:

Correct cost for the cell phone monthly plan = 54.2$

Explanation:

Price for monthly plan = 58.95$

Discount = 4.75 $

New cost found out by Sam = 11.45$

Discount considered by Sam = 58.95 - 11.45 = 47.5$

So, Instead of considering discount amount of 4.75$ Sam accidentally considered 47.5$, so he got 11.45$ as new cost for the cell phone plan.

Actual cost = 58.95 - 4.75 = 54.2$

Correct cost for the cell phone monthly plan = 54.2$

8 0

3 years ago

Please answer these two questions

Volgvan

The correct answer is two or four

6 0

3 years ago

To the nearest hundreth, what is the length of line segment AB?

FinnZ [79.3K]

Answer:

option (4)

Step-by-step explanation:

Calculate the length using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = A(2, 2) and (x₂, y₂ ) = B(- 6, 4)

AB = $\sqrt{(-6-2)^2+(4-2)^2}$

= $\sqrt{(-8)^2+2^2}$

= $\sqrt{64+4}$

= $\sqrt{68}$

≈ 8.25 ( to 2 dec. places )

3 0

3 years ago

Read 2 more answers

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$