Question

A gardener uses 1/3 of a liter of water to water 2/7 of a garden. Watering the entire garden at this rate will require _____ liters of water.

Answer 1

1 1/6 liters 
1/3 x 3 =1 liter and 6/7 of the garden watered divide 1/3 by two to get 1/7 of the garden t. add together to get 7/7

Answer 2

Answer:

$1\frac{1}{6}$ liter of water is needed to watering the entire garden at the given rate.

Step-by-step explanation:

Given : A gardener uses $\frac{1}{3}$ of a liter of water to watering $\frac{2}{7}$ of a garden.

Consider 1 Liter = 1 unit.

Hence, $\frac{1}{3}$ of a liter = $\frac{1}{3}$

We need to find how many liters of water is needed to watering the entire garden at this rate.

Let the total garden be x  parts then,

$\frac{2}{7}x=\frac{1}{3} \times 1$

$\frac{2}{7}x=\frac{1}{3}$

Dividing both side by  $\frac{2}{7}$ , we get,

$x=\frac{1}{3} \div \frac{2}{7}$

Applying $a\div b=a\times \frac{1}{b}$ , we get,

$x=\frac{1}{3} \times \frac{7}{2}$

$x=\frac{7}{6}$

Rewriting improper fraction into mixed fraction, we get,

$x=1\frac{1}{6}$

Thus, $1\frac{1}{6}$ liter of water is needed to watering the entire garden at the given rate.