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ehidna [41]
3 years ago
6

To the nearest hundreth, what is the length of line segment AB?

Mathematics
2 answers:
Lorico [155]3 years ago
7 0
The answer is BBB Bb
FinnZ [79.3K]3 years ago
3 0

Answer:

option (4)

Step-by-step explanation:

Calculate the length using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = A(2, 2) and (x₂, y₂ ) = B(- 6, 4)

AB = \sqrt{(-6-2)^2+(4-2)^2}

      = \sqrt{(-8)^2+2^2}

      = \sqrt{64+4}

      = \sqrt{68}

       ≈ 8.25 ( to 2 dec. places )

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If 4/9 of the 63 fishes in the tank were guppies. How many of the fish were not guppies
ArbitrLikvidat [17]
35 were not guppies.

Explanation:
63/9=7
7*4=28
63-28=35
8 0
3 years ago
In a triangle shown, which shows the correct order of the side lengths from smallest to largest.
Vera_Pavlovna [14]

Answer:

Not sure if there are options, but the order of side lengths from smallest to largest is <u>j, k, l</u>

Step-by-step explanation:

This is a bad explanation (sorry):

Side length order will be the same order of angle orders. By that, I mean the since angle C has the smallest angle, the side length across from it will also be the smallest. Since angle B is the biggest angle, side L will be the biggest length. This leaves angle A (and side k) in the middle.

5 0
3 years ago
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anyanavicka [17]

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4 0
3 years ago
Find the measure of the indicated arc
taurus [48]

Answer:

m(ABC) = 218°

Step-by-step explanation:

The measure of any arc with end points of an inscribed angle = 2 × inscribed angle

Inscribed angle = m<AMC = 109°

Intercepted arc = m(ABC)

Therefore,

m(ABC) = 2 × 109°

m(ABC) = 218°

7 0
3 years ago
triangle MNO is an equilateral triangle with sides measuring 16 units What is the height of the triangle?
fiasKO [112]

see the attached figure to better understand the problem

we know that

The equilateral triangle has three equal sides

so

in the equilateral triangle ABC

AB=BC=AC=16 units

the height of the triangle is the segment BD

in the right triangle BCD

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

solve for BD

BD^{2}=BC^{2}-DC^{2}

substitute the values

BD^{2}=16^{2}-8^{2}

BD^{2}=192

BD=\sqrt{192}\ units

therefore

<u>the answer is</u>

the height of the triangle is \sqrt{192}\ units


7 0
3 years ago
Read 2 more answers
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