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Zanzabum
2 years ago
14

Q 1-10

Physics
1 answer:
Over [174]2 years ago
6 0

The net force on the box perpendicular to the floor is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the box. Then

F[normal] = (35.5 kg) g = 347.9 N

Since the box slides with constant speed, the net force parallel to the floor is

∑ F[para] = F[applied] - F[friction] = 0

We have

F[friction] = 0.15 F[normal] = 52.185 N

so that

F[applied] = F[friction] ≈ 52 N

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Read 2 more answers
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