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3 years ago

10

Name three different avenues by which Thomas Edison received an education

1 answer:

klio [65]3 years ago

5 0

Edison's education is most unique and relevant.

1. The first teacher he had was his mother
2. He found vital lessons and was influenced greatly by the book of R.G. Parker called School of Natural Philosophy
3. Another educating piece he had was a book entitled The Cooper Union for the Advancement of Science and Art

His style of learning was though reading books on a variety of subjects, a self-educating environment that fosters independent learning which can be useful through his life.

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Why does the Rose advise Alice to go in the opposite direction?

Oliga [24]

Answer:

It’s is A

because the opposite direction will take her to the Red Queen

Explanation

8 0

3 years ago

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A positive or negative outcome of a decision or action can be called a

Mandarinka [93]

The answer to this would be :
<span>consequence
</span>hope that this helps you!
Source: I had done a research about this. =)

7 0

3 years ago

The gravitational force exerted by a proton on an electron is 2x1039 times weaker than the electric force that the proton exerts

pickupchik [31]

To solve this problem we will rely on the theorems announced by Newton and Coulomb about the Gravitational Force and the Electrostatic Force respectively.

In the case of the Force of gravity we have to,

$F_g = G\frac{m_pm_e}{d^2}$

Here,

G = Gravitational Universal Constant

$m_p$ = Mass of Proton

$m_e$ = Mass of Electron

d = Distance between them.

$F_g = (6.673*10^{-11} kg^{-1} \cdot m^3 \cdot s^{-2}) (\frac{(1.672*10^{-27}kg)(9.109*10^{-31})}{(52.9pm)^2})$

$F_g = 3.631*10^{-47}N$

In the case of the Electric Force we have,

$F_e = k\frac{q_pq_e}{d^2}$

k = Coulomb's constant

$q_p$ = Charge of proton

$q_e$ = Charge of electron

d = Distance between them

$F_e = (9*10^9N\cdot m^2 \cdot C^{-2})(\frac{(1.602*10^{-19}C)(1.602*10^{-19}C)}{(52.9pm)^2})$

$F_e = 82.446*10^{-9}N$

Therefore

$\frac{F_e}{F_g} = 2.270*10^{39}$

We can here prove that the statement is True

7 0

3 years ago

A 6.0-kg block slides from point A down a frictionless curve to point B. After the block passes point B, a friction force oppose

Setler [38]

Answer:

3.5kg

Explanation:

if you subtract 6-2.5 it equals 3.5

6 0

3 years ago

A stunt pilot in an air show performs a loop-the-loop in a vertical circle of radius 3.80 103 m. During this performance the pil

mr Goodwill [35]

The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s

<h3>What is apparent weight?</h3>

Apparent weight is a property of object that co-relates to the heaviness of the object.

It differs from the weight of an object as a result of the in-balance between the force acting on the object and an equal but opposite force

<h3>How to calculate the apparent weight</h3>

Formula:

Apparent weight = Real weight (mg) - m v∧2 ÷ r

Where m = mass

g = acceleration due to gravity = 9.8 m/s²

v = constant velocity = 2. 10 × 10∧2 m/s

r = radius = 3.80 × 10∧3 m

Note that weight = mg

m = weight ÷ g = 623 ÷ 9.8 = 63. 57 kg

a. Apparent wieight = 623 - (63. 57 × 2.10 × 10∧2 × 2.10 × 10∧2) ÷ 3.80 × 10∧3)

= 623 - (63.57 × 210) ÷ 3800

= 623 - 13377 ÷ 3800

= 623 - 3. 52

= 619.48 N

b. At weightless, weight = 0

Speed, V = √g× r = √ 9.8 × 3800 = √37,240 = 192. 97 m/s

Hence, The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s

Read more on apparent weight here:

brainly.com/question/11180653

#SPJ1

3 0

2 years ago