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nadya68 [22]
4 years ago
11

Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 1.25 kg of water d

ecreased from 113 °c to 55.0 °c.
Physics
1 answer:
algol [13]4 years ago
7 0

Energy change = -303050 J

Explanation:

the heat energy Q is given by the formula

Q= m C ΔT

m= mass of water=1.25 Kg

C= specific heat of water= 4180 J/Kg °C

ΔT= change in temperature =55-113= -58°C

Q= 1.25 (4180) (-58)

Q=-303050 J

Negative sign shows that the energy is released or lost.

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One of the most common methods for discovering and collecting latent fingerprints is by dusting a smooth or nonporous surface with fingerprint powder (black granular, aluminum flake, black magnetic, etc.). If any prints appear, they are photographed as mentioned above and then lifted from the surface with clear adhesive tape. The lifting tape is then placed on a latent lift card to preserve the print.
4 0
3 years ago
A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080
deff fn [24]

Answer:

Speed of 0.08 kg mass when it will reach to the bottom position is 1.94 m/s

Explanation:

When rod is released from rest then due to unbalanced torque about the hinge the system will rotate

Now moment of inertia of the system is given as

I = \frac{ML^2}{12} + \frac{m_1L^2}{4} + \frac{m_2L^2}{4}

now we have

M = 0.120 kg

m_1 = 0.02 kg

m_3 = 0.08 kg

now we have

I = \frac{0.120(0.90)^2}{12} + \frac{0.02(0.90)^2}{4} + \frac{0.08(0.90)^2}{4}

so we have

I = 8.1 \times 10^[-3} + 4.05 \times 10^[-3} + 0.0162

I = 0.02835

now by energy conservation we can say work done by gravity must be equal to change in kinetic energy

so we have

\frac{1}{2}I\omega^2 = m_1g \frac{L}{2} - m_2 g\frac{L}{2}

\frac{1}{2}(0.02835)\omega^2 = (0.08 - 0.02)(9.81)(0.45)

\omega = 4.32 rad/s

Now speed of 0.08 kg mass when it reaches to bottom point is given as

v = \omega \frac{L}{2}

v = 4.32 (0.45)

v = 1.94 m/s

3 0
4 years ago
if you exert 10.0 N of force to compress a spring 50 cm from its equilibrium point, then what is the spring constant?
Olegator [25]
The answer would be: b. The spring constant is 20 N/m
4 0
4 years ago
Can anyone heelp me plzz
lina2011 [118]

Answer:

the ans is D... good luck

3 0
3 years ago
Find initial velocity and time in air​
kkurt [141]

Answer:

The answer to your question is: v = 121.46 m/s

Explanation:

Data

h = 30 m

vo = ?

dx = 300 m

Formula

t = \sqrt{\frac{2h}{g}}

speed = distance / time

Process

t = \sqrt{\frac{2(30)}{9.81}} \\

t= 2.47 s

speed = 300 / 2.47

speed = v = 121.46 m/s

6 0
3 years ago
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