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2 years ago

Please help me with this also jjodlask

Mathematics

2 answers:

Verizon [17]2 years ago

7 0

<h3>Composite functions</h3>

When a function is substituted into another function it is known as a composite function.

<u>Given the following functions:</u>

f(x) = 4x + 3

g(x) = x - 2

Determine $f(g(x)) \ and \ g(f(x))$

$f(g(x)) = f(x-2)\\
f(x-2) = 4(x-2)+3\\
f(x-2)=4x-8+3\\
f(x-2) = 4x - 5\\
f(g(x)) = 4x - 4
$

1) Determine the value of $f(g(5))$

$f(g(5))=4(5) - 4\\
f(g(5))=20-4\\
f(g(5))=16$

2) For the function $g(f(-6))$

$g(f(-6))=4(-6) + 1\\
g(f(-6))=-24+1\\
g(f(-6))=-23$

3) For the value $f(f(7)),$ we need to determine $f(f(x))$

$f(f(x)) = f(4x+3)\\
f(f(x))= 4(4x+3)+3\\
f(f(x))=16x+12+3\\
f(f(x))=16x+15\\
f(f(7)) = 16(7) + 15\\
f(f(7)) = 127$

4) For the function $g(f(x));$

$g(f(x))=(4x+3)-2\\
g(f(x))=4x+3-2\\
g(f(x))=4x+1$

learn more on composite functions here: brainly.com/question/10687170

ikadub [295]2 years ago

7 0

Answer:

1. 15, 2. -23, 3. 220, 4. 4x-5

Step-by-step explanation:

f(x) = 4x + 3 g(x) = x - 2

1. f(g(5)): Put 5 in as x in g(x) 5 - 2 = 3. Now put the 3 as x into f(x) and solve. 4(3) + 3 = 15

2. g(f(-6)) 4(-6) + 3 = -21. -21 - 2 = -23

3. (f(f(7)) 4(7) + 3 = 31, 31(7) + 3 = 220

4. g(f(x)) 4(x-2) + 3 = 4x - 8 + 3 = 4x - 5

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PLEASE HELP!!! WILL GIVE BRAINLIEST!!!

777dan777 [17]

Answer: (2,2) and (-5,16)

Step-by-step explanation:

Here we have both Line (Linear Function) and Parabola (Quadratic Function)

So I am gonna write these equations here,

$y=x^2+x-4\\y=-2x+6$

The first equation has Parabola graph (Since it's second degree.)

and the second equation has line graph.

To find the intersection, you have to substitute either -2x+6 in first equation (Quadratic) or x^2+x-4 in second equation (Linear)

For me, I am going to substitute x^2+x-4 in y=-2x+6.

$x^2+x-4=-2x+6$

Now solve the equation and find the value of x.

Since it's Quadratic Equation (Because there's x^2) I'd move -2x+6 to the left side.

$x^2+x-4+2x-6=0$ Finish things here (Subtract and Addition)

$x^2+3x-10=0$ What two numbers multiply to 10? Find the factors of 10, that are [1 and 10] and [2 and 5]

Now think about it, do you think that if 1 and 10 subtract or even addition, do you think that it'd be 3? No, of course not.

So 2 and 5 is right.

$(x-2)(x+5)=0$ (5-2 = 3) and (5*(-2) = -10)

Then we get both x, $x=2,-5$

However, this is not it. You have to substitute both x in Linear Equation.

Substitute x = 2 in y=-2x+6

$y=-2(2)+6\\y=-4+6\\y=2$

Order = $(2,2)$

Then substitute x = -5 in y=-2x+6

$y=-2(-5)+6\\y=10+6\\y=16$

Order = $(-5,16)$

So the intersections are both (2,2) and (-5,16) as shown in graph below.

4 0

3 years ago

How can I use benchmarks to estimate 9/10+4/10

Jobisdone [24]

I don’t kno how to estimate using benchmarks but I kno the exacts answer is 13/10 or 1.3

4 0

3 years ago

8 books cost \$19.60$19.60dollar sign, 19, point, 60.

snow_tiger [21]

Answer: C=[ (10) x (19.60)÷ (8)]

Step-by-step explanation:

Given , The cost of 8 books = $ 19.60

Then, By UNITARY method , the cost of one book = ( Cost of 8 books ) ÷ ( 8)

i.e. The cost of one book = ($19.60) ÷ ( 8) ...(i)

Now , cost of 10 books = (10) x (Cost of one book)

From (i) , we get

Cost of 10 books =$[ (10) x (19.60)÷ (8)]

Let C be the cost of 10 books ( in dollars) .

So , the equation would help determine the cost of 10 :

C=[ (10) x (19.60)÷ (8)]

7 0

3 years ago

In need of help please

Alisiya [41]

Answer:

Step-by-step explanation:

1-4

n=30/1

so it would be (t,n) instead of (x,y) respectively

so the first would be (1,30)

2. n=30/2

second would be (2,15)

3. n=30/3

third would be (3,10)

n=30/4

fourth would be (4,7.5)

7 0

3 years ago

Solve the system of equations by elimination.<br> 2x - y + 3z=-1<br> x + 2y - 4z=-1<br> y – 2z=0

MrRa [10]

Answer:

x = -1, y = 2 and z = 1

Step-by-step explanation:

The given system of equations are :

2x - y + 3z= -1 ....(1)

x + 2y - 4z = -1 ......(2)

y – 2z = 0 .....(3)

Equation (3) can be written as :

y = 2z

Use y = 2z in equation (2)

x + 2(2z) - 4z = -1

x + 4z - 4z = -1

x = -1

Put the value of x in equation (1) :

-2 -y +3z = -1

-y+3z = 1 ....(4)

Adding equation (3) and (4)

y-2z+(-y+3z)=1

z = 1

Now put z = 1 in equation (4)

-y+3=1

-y = -2

y = 2

Hence, the values of x,y and z are -1, 2 and 1 respectively.

6 0

3 years ago

Please help me with this also jjodlask​

Please help me with this also jjodlask