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IgorLugansk [536]
2 years ago
11

Find the general solution of the given differential equations. Give the largest interval I over which the general solution is de

fined. Determine whether there are any transient terms in the general solution.
y' + 2xy = (x^3)

ydx = (y(e^y) - 2x)dy

(dP)/(dt) + 2tP = P + 4t - 2
Mathematics
1 answer:
e-lub [12.9K]2 years ago
4 0
The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)

The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
</span>
The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>
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Answer:

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x−2=−3 

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3 years ago
The expression 3(x - 9) is equivalent to....
MrMuchimi

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d

Step-by-step explanation:

3(x - 9)

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2 years ago
BE is an angle bisector of ABE =2x+20 and mEBC=4x-6 determine m ABE
Mashcka [7]

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3 years ago
Jon ran around a track that was 1/8 of a mile long. He ran around the track 24 times. How many miles did Jon run?
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1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 8/8 so 8 laps = 1 miles.

24/8= 3... so that mean he ran 3 miles around the track, to check work:

1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 8/8 so 8 laps = 1 miles.
1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 8/8 so 8 laps = 1 miles.
1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 8/8 so 8 laps = 1 miles.

if you count how many 1/8 there are you'll get 24 '1/8' therefore you know your answer is correct.
5 0
3 years ago
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