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IgorLugansk [536]
3 years ago
11

Find the general solution of the given differential equations. Give the largest interval I over which the general solution is de

fined. Determine whether there are any transient terms in the general solution.
y' + 2xy = (x^3)

ydx = (y(e^y) - 2x)dy

(dP)/(dt) + 2tP = P + 4t - 2
Mathematics
1 answer:
e-lub [12.9K]3 years ago
4 0
The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)

The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
</span>
The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>
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6,24,96,384,1536, what's the next sequence number
svetoff [14.1K]
4608
Its being times by three so 24*24*24 equals 96 hope it helps

3 0
3 years ago
Read 2 more answers
Can someone help me?
r-ruslan [8.4K]
4x +31 = 35
6x +39 = 45
35 + 45 = 80 
I believe it would be 80
4 0
4 years ago
Find (3a2 - 2a + 4) - (a2 - 3a + 7) .
melisa1 [442]
<span>(3a^2 - 2a + 4) - (a^2 - 3a + 7) = (distribute the negative sign)
3a^2 - 2a +4 - a^2 + 3a - 7 = (add like terms)
2a^2 + a - 3
So, the answer is A!

</span>
6 0
3 years ago
3x + 2y + z = 8 2x - 3y + 2z = -16 x + 4y - z = 20
padilas [110]
I'll do a similar problem, and I challenge you to do this on your own using similar methods!

x+5y+2z=23
8x+4y+3z=12
9x-3y-7z=-10

Multiplying the first equation by -8 and adding it to the second one (to get rid of the x) and also multiplying the first equation by -9 and adding the third one to get rid of the x there too, we end up with

-36y-13z=-92
and
-48y-25z=-217

Multiplying both equations by -1, we get
36y+13z=-92
48y+25z=217

Multiplying the (new) first equation by -4/3 and adding it to the second (to get rid of the y), we get
(7+2/3)z=94+1/3

Dividing both sides by (7+2/3) to separate the z, we get
z=\frac{282/3}{23/3} = \frac{282}{23}

Plugging that into 
48y+25z=217, we can subtract 25z from both sides and divide by 48 to get 
y= \frac{217-25z}{48} =\frac{217-25*282/23}{48}

Lastly, we plug this into x+5y+2z=23 to get
x=23-5y-2z by subtracting 5y+2z from both sides to get 
x=23- \frac{217-25*282/23}{48}*5-2*282/23 

Good luck, and feel free to ask with any questions!
4 0
3 years ago
Solve each problem using the quadrat<br> answer)<br> 9.) x2 - 6x + 25 = 0
Nikitich [7]

Answer:

There are 2 complex roots:

3 - 4i, 3 + 4i.

Step-by-step explanation:

x^2 - 6x + 25 = 0

Using the quadratic formula:

x = [-(-6) ± √(-6)^2 - 4*1*25)] / 2

= (6 ± √-64)/2

= 3 ± 8i/2

= 3 ± 4i

3 0
3 years ago
Read 2 more answers
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