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Levart [38]
2 years ago
12

A firm has the following fixed proportion production function q = min(k, 2l). a. Find the firms long-run total, average, and mar

ginal cost functions. b. Suppose that k is fixed at 20 in the short run. Calculate the firms short-run total, average, and marginal cost functions. c. Suppose v = 1 and w = 3. Calculate this firms long-run and short-run average and marginal cost curves. Q4. A firm’s production function is given by q = 2z1 + 3z2. Given the input prices, w1 for z1 and w2 for z2. a. Find the input demands z1 and z2 minimizing the cost of producing the level of output q. b. Find the cost function for producing the level q.​
Mathematics
1 answer:
Yuri [45]2 years ago
3 0

Answer:

I think its right

Step-by-step explanation:

a) In the long run, we have, 5k=10 and k=2l Thus, C=2l+3l= 5l=0.5q Thus, AC=5l/10l =0.5 MC=0.5 b) In the short run, k=10 Q=min(50,10l) If l<5, q=10l. C=10+3l= 10+0.3q Thus, AC=10/q + 0.3 If l>5, q=50. C= 10+3l AC= (10+3l)/50 If q>50, then MC...

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the number y of oranges is used to make c pints of orange juice if represented by the equation y=8x. Graph the equation
abruzzese [7]

Answer:

y=8x

8x=y

Step-by-step explanation:

8 0
2 years ago
Which function has a range of y &lt; 3?<br> y=3(2)*<br> y=2(3)<br> y=-(2)*+ 3<br> O y=(2]*_3
jasenka [17]

Answer:

The function given by y = - (2)^{x} + 3 will have a range of y < 3.

Step-by-step explanation:

The function given by y = - (2)^{x} + 3 will have a range of y < 3.

This is because, for any real values of x, the term - (2)^{x} will have a negative value. If we put x = 1, then, - (2)^{x} = - 2, and for x = -1, then - (2)^{x} = - 0.5.

That means - (2)^{x} < 0 for all real x.

Hence, - (2)^{x} + 3 < 0 + 3

⇒ y < 3 for all real x. (Answer)

7 0
3 years ago
Match each quadratic equation with its solution set.
Marianna [84]

Answer:

( 8 , - 8)  => x² - 55 = 9

( 4 , - 4)  =>  2x² - 32 = 0

(5 , - 5) => 4x² - 100 = 0

(11 , - 11) => x² - 140 = -19

( 3, - 3) =>  2x² - 18 = 0

Step-by-step explanation:

1)

2x^2  - 32 = 0\\\\2(x^2 - 16 ) = 0 \\\\x^2 - 16 = 0 \\\\x^2 = 16 \\\\x = \sqrt {16 }  = \pm 4

x = ( 4 , - 4)

2)

4x^2 - 100 = 0 \\\\4(x^2 - 25 ) = 0\\\\x^2 - 25 = 0 \\\\x^2 = 25 \\\\x= \sqrt{25} = \pm 5

x = ( 5 , - 5 )

3)

x^2 - 55 = 9 \\\\x^2 = 9 +55\\\\x^2 = 64\\\\x = \sqrt{64} = \pm 8

x= ( 8 , - 8)

4)

x^2 - 140 = - 19\\\\x^2 = -19 + 140 \\\\x^2 = 121 \\\\x= \sqrt{121} = \pm 11

x = ( 11  , -11)

5)

2x^2 - 18 = 0\\\\2(x^2 - 9) = 0\\\\x^2- 9 = 0 \\\\x^2 = 9 \\\\x = \sqrt9 = \pm 3

x = ( 3 , - 3)

8 0
3 years ago
Read 2 more answers
Simulate the rolling of two dice 10,000 times. (b) Identify which rolls of the dice are in the event A, the dice add up to a per
dexar [7]

Answer:

Answer explained below

Step-by-step explanation:

(a)

Simulate the rolling of two dice 10,000 times D1 and D2 are the 10,000 results of roll of dice 1 and dice 2.

D1 = sample(c(1:6), 10000, replace = TRUE)

D2 = sample(c(1:6), 10000, replace = TRUE)

Sum = D1 + D2

(b)

The event A, the dice add up to a perfect square (4 or 9).

A = Sum[Sum == 4 | Sum ==9]

Proportion of A, P(A) = 0.189

length(A) / length(Sum)

(c)

The event B, the dice add up to an even number.

B = Sum[Sum %% 2 == 0]

Proportion of B, P(B) = 0.5049

length(B) / length(Sum)

(d)

The  rolls are in A ∩ B (common to both A and B)

> intersect(A,B)

[1] 4

The proportion that are in A ∩ B is 0.0792

length(Sum[Sum == 4]) / length(Sum)

P(A) * P(B) = 0.189 * 0.5049 = 0.0954

The proportion in A multiplied by the proportion that are in B is not equal to P(A ∩ B)

(e)

Of the rolls in which B occurs, the proportion of those rolls are also in A is 0.4190476

length(Sum[Sum == 4]) / length(A)

This proportion is greater than the P(A) calculated in part (b).

4 0
3 years ago
How do you do this question?
quester [9]

Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

F(x) is the area under f(t) between t=a and t=x.  When x=a, the width of the interval is 0, so the area is zero.

F(6) = 0, so a = 6.

F(x) = ∫₆ˣ t⁷ dt

F(6) = ∫₆⁶ t⁷ dt

F(6) = 0

3 0
3 years ago
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