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Levart [38]
2 years ago
12

A firm has the following fixed proportion production function q = min(k, 2l). a. Find the firms long-run total, average, and mar

ginal cost functions. b. Suppose that k is fixed at 20 in the short run. Calculate the firms short-run total, average, and marginal cost functions. c. Suppose v = 1 and w = 3. Calculate this firms long-run and short-run average and marginal cost curves. Q4. A firm’s production function is given by q = 2z1 + 3z2. Given the input prices, w1 for z1 and w2 for z2. a. Find the input demands z1 and z2 minimizing the cost of producing the level of output q. b. Find the cost function for producing the level q.​
Mathematics
1 answer:
Yuri [45]2 years ago
3 0

Answer:

I think its right

Step-by-step explanation:

a) In the long run, we have, 5k=10 and k=2l Thus, C=2l+3l= 5l=0.5q Thus, AC=5l/10l =0.5 MC=0.5 b) In the short run, k=10 Q=min(50,10l) If l<5, q=10l. C=10+3l= 10+0.3q Thus, AC=10/q + 0.3 If l>5, q=50. C= 10+3l AC= (10+3l)/50 If q>50, then MC...

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2x^2 + 3x - 12 when x = 5 help pls
cluponka [151]

\huge\textsf{Hey there!}

\mathsf{2x^2 + 3x - 12}

\mathsf{= 2(5)^2 + 3(5) - 12}

\mathsf{5^2}

\mathsf{= 5 \times 5}

\mathsf{\bf = 25}

\mathsf{2(25) + 3(5) - 12}

\mathsf{2(25)}

\mathsf{= \bf 50}

\mathsf{3(5)}

\mathsf{= \bf 15}

\mathsf{= 50 + 15 -  12}

\mathsf{50 + 15}

\mathsf{= \bf 65}

65 - 12

\mathsf{= \bf 53}

\boxed{\boxed{\huge\textsf{Answer: \bf 53}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

5 0
2 years ago
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Find the slope of the line that<br> passes through the following<br> points. (0,0), (-2,-4)
Ann [662]

Answer:

m=2

Step-by-step explanation:

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Answer:

i think the answer is B but don't take my word for it


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WHY ISNT ANYBODY ANSWERING MY QUESTION PS HELP MEEEEE I ALWAYS GIVE BRAINLIEST 5 STARS andddd offer 25 pointsssssssssss plsss he
meriva

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6 0
3 years ago
4. 9d - 5 = 4<br><br> What does d =<br> 5. 6-3w=-27 what does w =<br> 6. -4= q/8-19 what does q =
trapecia [35]

Answer:

4) d = 1

5) w = 11

6) q = 120

Step-by-step explanation:

<em>4)</em> 9d - 5 = 4

Adding 5 on both the sides ,

=  > 9d - 5 + 5 = 4 + 5

=  > 9d = 9

Dividing both the sides by 9 ,

=  >  \frac{9d}{9}  =  \frac{9}{9}

=  > d = 1

<em>5)</em> 6 - 3w =  - 27

Substracting 6 from both the sides ,

6  - 3w - 6 =  - 27 - 6

=  >  - 3w =  - 33

Dividing both the sides by -3 ,

=  >  \frac{ - 3w}{ - 3}  =  \frac{ - 33}{ - 3}

=  > w = 11

<em>6)</em> - 4 =  \frac{q}{8}  - 19

Adding 19 on both the sides ,

\frac{q}{8}  - 19 + 19 = - 4 + 19

=  >  \frac{q}{8}  = 15

Multiplying both the sides by 8 ,

=  >  \frac{q}{8}  \times 8 = 15 \times 8

=  > q = 120

6 0
2 years ago
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