(a).
The product of two binomials is sometimes called FOIL.
It stands for ...

   the product of the First terms (3j x 3j)
plus
   the product of the Outside terms (3j x 5)
plus
   the product of the Inside terms (-5 x 3j)
plus
   the product of the Last terms (-5 x 5)

FOIL works for multiplying ANY two binomials (quantities with 2 terms).

Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .

Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.

Whenever you have

      (the sum of two things) x (the difference of the same things)

the product is going to be

   (the first thing)² minus (the second thing)² .

So in (a), that'll be (3j)² - (5)² = 9j² - 25 .

You could find the product with FOIL, or with this easier tool.
______________________________

(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:

(4h + 5) x (4h + 5) .

You can do the product with FOIL, or use another little tool:

The square of a binomial (4h + 5)² is ...

   the square of the first term    (4h)²
plus
   the square of the last term       (5)²
plus
   double the product of the terms 2 · (4h · 5)
________________________________

(c).
Use the tool I gave you in part-a . . . twice .

The product of the first 2 binomials is    (g² - 4) .

The product of the last 2 binomials is also (g² - 4) .

Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .

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Step-by-step explanation:

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