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2 years ago

Point A is located at (-4, -5). After it is translated, point A' is located at (-4, 1). What was the translation?

Mathematics

1 answer:

RUDIKE [14]2 years ago

4 0

Answer: 6 units up

Step-by-step explanation:

because -5 +6 is 1, we know that the translation is 6 units up

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Write a real-world problem involving a percent that can be solved by using the proportion 3/b= 60/100. Then solve the proportion

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Dax goes to the store to buy milk. There is a sale for milk, and it now costs 3 dollars since it was 60% off. What was the original price of the milk?
3 - 60
x - 100
Cross multiply
300=60x
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The milk original cost 5 dollars.

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2 years ago

I have a test and only have an hour please hurry! 90 / 3* (9 +6)=?

Alex777 [14]

90/3=30 30*(15)=450 450 is your answer.

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3 years ago

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2 ( -2w - 1.2 + 7x) =

PSYCHO15rus [73]

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3 years ago

Please any one help me

Ulleksa [173]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Since it's a Trapezoid with its non - parallel sides equal to one another,

$\qquad \sf \dashrightarrow \:\angle A + \angle P = 180$

[ By forming co - interior angle pair ]

$\qquad \sf \dashrightarrow \:\angle A +100 = 180$

$\qquad \sf \dashrightarrow \:\angle A = 180 - 100$

$\qquad \sf \dashrightarrow \:\angle A = 80$

Now, similarly,

$\qquad \sf \dashrightarrow \:\angle A + \angle R = 180$

$\qquad \sf \dashrightarrow \: \angle R + 80 = 180$

$\qquad \sf \dashrightarrow \: \angle R = 100$

Similarly,

$\qquad \sf \dashrightarrow \angle K + \angle R = 180$

$\qquad \sf \dashrightarrow \angle K + 100 = 180$

$\qquad \sf \dashrightarrow \angle K = 80$

3 0

2 years ago

Read 2 more answers

Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students

Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that , $\text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}$

Then , for section A :

$\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}$

$\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200$

Similarly in Section B, $\text{Sum of scores in sec B}=90\times20=1800$

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz = $\dfrac{\text{Total score}}{\text{Total students}}$

$=\dfrac{3000}{35}=85.7142857143\approx85.7$

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0

2 years ago