Question

3. a car takes off with initial velocity of 20m/s and move with uniform acceleration of 12m/s2 for 20s. It maintained a constant velocity for 30s and come to rest with uniform acceleration of 2m/s2. Calculate the total distance covered by the car.​

Answer 1

The total distance traveled by the car at the given velocity and time is 900 m.

The given parameters:

• initial velocity of the car, u = 20 m/s
• acceleration of the car, a = 12 m/s²
• time of motion of the car, t = 20 s
• final time = 30 s
• final acceleration = 2 m/s²

The final time of motion of car before coming to rest is calculated as follows;

$v_f = v_0 -at\\\\0 = 20 - 2t\\\\t = 10 \ s$

The graph of the car's motion is in the image uploaded.

The total distance traveled by the car is calculated as follows;

$total \ distance = A \ + B \ + C\\\\total \ distance = (\frac{1 }{2} \times 20 \times 20) \ + (20 \times 30) \ + (\frac{1}{2}\times 10 \times 20)\\\\total \ distance = 900 \ m$

Thus, the total distance traveled by the car at the given velocity and time is 900 m.

Learn more about velocity-time graph here: brainly.com/question/24874645