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Verizon [17]
3 years ago
14

3. a car takes off with initial velocity of 20m/s and move with uniform acceleration of 12m/s2 for 20s. It maintained a constant

velocity for 30s and come to rest with uniform acceleration of 2m/s2. Calculate the total distance covered by the car.​
Physics
1 answer:
lions [1.4K]3 years ago
3 0

The total distance traveled by the car at the given velocity and time is 900 m.

The given parameters:

  • <em>initial velocity of the car, u = 20 m/s</em>
  • <em>acceleration of the car, a = 12 m/s²</em>
  • <em>time of motion of the car, t = 20 s</em>
  • <em>final time = 30 s</em>
  • <em>final acceleration = 2 m/s²</em>

The final time of motion of car before coming to rest is calculated as follows;

v_f = v_0 -at\\\\0 = 20 - 2t\\\\t = 10 \ s

The graph of the car's motion is in the image uploaded.

The total distance traveled by the car is calculated as follows;

total \ distance = A \ + B \ + C\\\\total \ distance = (\frac{1 }{2} \times 20 \times 20) \ + (20 \times 30) \ + (\frac{1}{2}\times 10 \times 20)\\\\total \ distance = 900 \ m

Thus, the total distance traveled by the car at the given velocity and time is 900 m.

Learn more about velocity-time graph here: brainly.com/question/24874645

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Answer:

True

Explanation:

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5 0
3 years ago
1) For a positive point charge, the lines radiate ………. . While, for a negative point charge, the lines converge …………. .
ch4aika [34]

Answer:

For a positive point charge, the lines radiate <u>outwards</u>, while for a negative point charge, the lines converge<u> inwards.</u>

Explanation:

A single point charges produces an electric field which has a radial shape.The sign of a charge determines the the direction of the field. In Positive charge have the direction of field is out of the charge and for negative charge, the direction of field is towards the charge.This behavior is in relation to how a positive test charge will experience in a field.

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You are investigating the report of a UFO landing in an isolated portion of New Mexico, and encounter a strange object that is r
SIZIF [17.4K]

Answer: 5 m

Explanation:

We have the following data:

I_{1}=0.11 W/m^{2} is the intensity of the sound at 7.5 m from the source

r_{1}=7.5 m is the distance at which the intensity I_{1} was measured

I_{2}=1 W/m^{2} is the intensity of the sound at r_{2} from the source

We have to find r_{2}

Since the object is radiating the signal uniformly in all directions, we can use the <u>Inverse Square Law for Intensity:</u>

\frac{I_{1}}{I_{2}}=\frac{r_{2}^{2}}{r_{1}^{2}}

Isolating r_{2}:

r_{2}=r_{1}\sqrt{\frac{I_{1}}{I_{2}}}

r_{2}=7.5 m\sqrt{\frac{0.11 W/m^{2}}{1 W/m^{2}}}

r_{2}=2.48 m This is the distance at which the intensity is the "threshold of pain"

Now, we have to substract this value to r_{1} to find how much closer to the source can we move:

r_{1}-r_{2}=7.5 m - 2.48 m=5.02 m \approx 5 m

3 0
3 years ago
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Answer:

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Explanation:

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hope this helps!^^

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