Question

1) what is the potential energy at the end of the loop?

Answer 1

The potential energy at the end of the loop is equal to 0.3407 Joules.

Given the following data:

• Mass of rock = 102.16 g to kg = 0.10216 kilogram.

• Height of the loop = 34 cm to m = 0.34 meter.

• Acceleration due to gravity = 9.8 $m/s^2$

What is potential energy?

Potential energy (P.E) refers to the energy that is possessed by an object due to its position (height) above planet Earth.

Mathematically, potential energy (P.E) is given by this formula;

$P.E = mgh$

Where:

• m is the mass of an object.

• g is the acceleration due to gravity.

• h is the height of an object.

Substituting the given parameters into the formula, we have;

$P.E = 0.10216 \times 9.81 \times 0.34$

P.E = 0.3407 Joules.

What is kinetic energy?

Kinetic energy (K.E) refers to an energy that is possessed by a physical object due to its motion.

Mathematically, kinetic energy (K.E) is given by this formula;

$K.E = \frac{1}{2} MV^2$

Note: You'll have to calculate the velocity from the distance traveled by the car and photogate time in your experiment.

Based on the law of conservation of energy, we can deduce the following points:

• Potential energy (P.E) is highest at the top of the loop while kinetic energy (K.E) is lowest.

• Kinetic energy (K.E) is highest underneath the loop while potential energy (P.E) is lowest.

Read more on potential energy here: brainly.com/question/8664733