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katovenus [111]
3 years ago
14

A spring is stretched to a displacement of 3.4 m from equilibrium. Then the spring is released and allowed to recoil to a displa

cement of 1.9 m from equilibrium. The spring constant is 11 N/m. What best describes the work involved as the spring recoils?
Physics
1 answer:
Stells [14]3 years ago
5 0
Answer to A spring<span> is </span>stretched<span> to a </span>displacement<span> of </span>3.4 m<span> from </span>equilibrium<span>. </span>Then<span> the </span>spring<span> is</span>released<span> and ... </span>Then<span> the </span>spring<span> is </span>released<span> and </span>allowed<span> to </span>recoil<span> to a </span>displacement<span> of </span>1.9 m<span> from</span>equilibrium<span>. The </span>spring constant<span> is </span>11 N/m<span>. What </span>best describes<span> the </span>work involved<span> as the </span>spring recoils<span>? A)87 J of </span>work<span> is performed ...</span>
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For a specific volume of 0.2 m3/kg, find the quality of steam if the absolute pressure is (a) 40 kPa and (b) 630 kPa. What is th
ICE Princess25 [194]

Answer:

x=0.0498

x'=0.659

Explanation:

Specific Volume V=0.2m_3/kg

Absolute Pressure (a) P_a= 40kpa

Giving

T_a=75.87

v_f=1.265*10^{-3}m^3/kg

v_g=3.993m^3/kg

                               (b) P_a= 630kpa

Giving

T_b=160.13C

v_f'=1.10282*10^{-3} m^3/kg

v_g'=0.30286 m^3/kg

(a)

Generally the equation for quality of Steam X  is mathematically given by

x=\frac{v-v_f}{v_g-v_f}

x=\frac{0.2-1.0265*10^{-3}}{3.993-1.0265*10^{-3}}

x=0.0498

(b)

Generally the equation for quality of Steam X  is mathematically given by

x'=\frac{v-v_f'}{v_g'-v_f'}

x'=\frac{0.2-1.10*10^{-3}}{3.30-1.1*10^{-3}}

x'=0.659

4 0
3 years ago
A 100 N force is applied to move an object a horizontal distance of 5 meters at constant speed in 10 seconds. How much power is
Tpy6a [65]

Answer:

50 W

Explanation:

<h3><u>Given :</u></h3>

  • Force applied = 100 N
  • Distance covered = 5 metres
  • Time = 10 seconds

<h3><u>To find :</u></h3>

Power

<h3><u>Solution :</u></h3>

For calculating power, we first need to know about the work done.

\bf \boxed{Work = Force \times displacement}

Now, substituting values in the above formula;

Work = 100 × 5

= 500 Nm or 500 J

We know that,

\bf \boxed{Power=\dfrac{Work\:done}{Time\: taken}}

Substituting values in above formula;

Power = 500/ 10

= 50 Nm/s or 50 W

Hence, power = 50 W .

5 0
3 years ago
Please help me , I also have to show work on paper
kramer

Answer:

Choose B

Explanation:

Hope Can I help you

7 0
3 years ago
What do we have seasons on earth
Goryan [66]

Because the Earth's axis is not "straight up and down" as we move
around the sun. 

So when we're on one side of the sun, the top pole leans slightly toward
the sun.  During that time the sun shines more directly on the top half
of the Earth, and less directly on the bottom half.  The people on the
top half see the sun higher in the sky, and their weather is warmer,
while the people on the bottom half see the sun lower in the sky, and
their weather is cooler.

Then, when we're on the other side of the sun, the top pole leans slightly
away from the sun.  During that time the sun shines more directly on the
bottom half of the Earth, and less directly on the top half.  The people on
the bottom half see the sun higher in the sky, and their weather is warmer,
while the people on the top half see the sun lower in the sky, and their
weather is cooler.

The Earth makes the complete trip around the sun in one year, so the
people on the Earth go through this cycle of higher/lower sun and
warmer/cooler weather every year.

8 0
3 years ago
A 1.5kw vacuum cleaner is used for half an hour. Calculate its energy usage.​
juin [17]

Answer:

its energy usage is 0.05

Explanation:

1.5kw/30=0.05

8 0
2 years ago
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