A spring is stretched to a displacement of 3.4 m from equilibrium. Then the spring is released and allowed to recoil to a displa
1 answer:
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Answer:
The work done by the frictional force is 600J.
Explanation:
The work done by the frictional force is
.
Now, and
; therefore,
Hence, the work done by friction is 660J.
Answer:
22600 cm³ (3 s.f.)
Explanation:
Please see the attached picture for the full solution.
The magnitude of the current in wire 3 is 2.4 A and in a direction pointing in the downward direction.
- The force per unit length between two parallel thin current-carrying
and
wires at distance ' r ' is given by
....(1) .
- If the current is flowing in both wires in the same direction, and the force between them will be the attractive force and if the current is flowing in opposite direction in wires then the force between them will be the repulsive force.
A schematic of the information provided in the question can be seen in the image attached below.
From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3
Using equation (1) , we get
I₃ = 2.4 A and the current is pointing in the downward direction
Learn more about the magnitude and direction of forces here:
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